call-by-value Questions
4
Solved
I want to know what is call-by-need.
Though I searched in wikipedia and found it here: http://en.wikipedia.org/wiki/Evaluation_strategy,
but could not understand properly.
If anyone can explain w...
Desai asked 2/4, 2011 at 21:37
5
Solved
Concerning objects (especially strings), call by reference is faster than call-by-value because the function call does not need to create a copy of the original object. Using const, one can also en...
Abrahan asked 19/3, 2015 at 10:7
2
Solved
def getStr(): String = {
println("getStr is running")
"str"
}
def lazyHello(para: => String) = {
println("lazy hello is runing")
println(para)
}
def notLazyHello(para: String) = {
println...
Tnt asked 19/11, 2013 at 12:58
1
Solved
I have the following two functions:
Class foo(Class arg)
{
return arg;
}
Class bar(Class *arg)
{
return *arg;
}
Now, when I solely call foo(arg), the copy constructor is of course called twic...
Decastyle asked 12/5, 2013 at 11:58
5
Solved
public class StackOverFlow {
public static void main(String[] args) {
ArrayList<String> al = new ArrayList<String>();
al.add("A");
al.add("B");
markAsNull(al);
System.out.pr...
Vines asked 8/4, 2013 at 5:23
1
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