I am a little bit confused by how movzx behaves in the following example. (Please note that I am assuming the print_int function used in my code sample works and the problem is not there but in my ...

I'm looking at the following disassembled AArch64 instruction: 65 6E 20 2B adds w5, w19, w0, uxtx #3 According to the ARM manual, uxtx zero-extends w0 to an unsigned 64-bit value before adding it ...

In the x86-64 Tour of Intel Manuals, I read Perhaps the most surprising fact is that an instruction such as MOV EAX, EBX automatically zeroes upper 32 bits of RAX register. The Intel documentatio...

I can tell this is a super simple problem but I have yet to figure it out. Basically, I just want to be able to take one element an array and add and subtract some numbers from it using registers a...

I decided to learn an assembly programming language. I am using this 8086 tutorial. At the bottom the exercise is to find an error in some instructions and one of them is mov cx, ch I fo...

What exactly does this instruction do? movzbl 0x01(%eax,%ecx), %eax

As it is widely advertised, modern x86_64 processors have 64-bit registers that can be used in backward-compatible fashion as 32-bit registers, 16-bit registers and even 8-bit registers, for ...

When assembling this code with nasm: BITS 64 mov eax, 0x1 mov rax, 0x1 I get this output: b8 01 00 00 00 b8 01 00 00 00 which is the opcode for mov eax, 0x1 repeated twice. Does this mean th...

Alright, so I am dealing with the following snippet of code: push %ebp mov %esp,%ebp push %ebx mov 0x8(%ebp),%eax movzwl %ax,%edx So this behaves as expected when dealing with positive values....

I can't seem to grasp the concept on these stuff, even with the help of Google and a textbook in my hand. Following the format (opcode, rs, rt, offset)... Do you sign extend the offset before ad...