I would like to make the following sequence in R, by using rep or any other function. c(1, 2, 3, 4, 5, 2, 3, 4, 5, 3, 4, 5, 4, 5, 5) Basically, c(1:5, 2:5, 3:5, 4:5, 5:5).

I am trying to replicate a dataframe (zoo object) 50 times as a whole, and get the result as a matrix, but all the commands I have tried seems to be unsuccessful. I could easily write a function th...

Begin a new R session with an empty environment. Write a series of functions with a parameter that is to be used as the value of the times parameter in a call to rep(). f <- function(n) { rep(...

I am trying to generate a vector containing decreasing sequences of increasing length, such as 1, 2,1, 3,2,1, 4,3,2,1, 5,4,3,2,1, i.e. c(1, 2:1, 3:1, 4:1, 5:1) I tried to use a loop for this, but I...

I would like to create a sequence from two numbers, such that the occurrence of one of the numbers decreases (from n_1 to 1) while for the other number the occurrences are fixed at n_2. I've been...

I am trying to calculate a median value across a number of columns, however my data is a bit funky. It looks like the following example. library(data.table) dt <- data.table("ID" = c(1,2,3,4),...

I want to create a list which is eight times the vector c(2,6), i.e. a list of 8 vectors. WRONG: object = as.list(rep(c(2,6),8)) results instead in a list of 16 single numbers: 2 6 2 6 2 6 2 6 .....

How to assign more than one value for "each" argument in "rep" function in R? A trivial example, where each value in a vector is 3-times repeated in a row: a <- seq(2,6,2) rep (a,each = 3) H...

When I perform: rep(1:4, rep(4,4)) I get 1 1 1 1 2 2 2 2 3 3 3 3 4 4 4 4 which is expected. But then when I try to fix the length to 16(which is the length of the output) as follows: rep(1...

x=1:20 [1] 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 rep(x,2) [1] 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 View(r...

I have a data frame with 1666 rows. I would like to add a column with a repeating sequence of 1:5 to use with cut() to do cross validation. It would look like this: Y x1 x2 Id1 1 .15 3.6 1 0 1.1...