Use the length.out
argument of rep()
(or rep_len
, a "faster simplified version"):
> rep(1:5, length.out = 166) # or rep_len(1:5, 166)
# [1] 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 1 2
# [38] 3 4 5 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 1 2 3 4
# [75] 5 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 1
# [112] 2 3 4 5 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 1 2 3
# [149] 4 5 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 1
length.out
: non-negative integer. The desired length of the output vector
Here is an example using the built-in dataset cars.
str(cars)
'data.frame': 50 obs. of 2 variables:
$ speed: num 4 4 7 7 8 9 10 10 10 11 ...
$ dist : num 2 10 4 22 16 10 18 26 34 17 ...
Add grouping column:
cars$group <- rep(1:3, length.out = 50L)
Inspect the result:
head(cars)
speed dist group
1 4 2 1
2 4 10 2
3 7 4 3
4 7 22 1
5 8 16 2
6 9 10 3
tail(cars)
speed dist group
45 23 54 3
46 24 70 1
47 24 92 2
48 24 93 3
49 24 120 1
50 25 85 2