quantified-constraints Questions

1

Solved

Previously, in order to use quantified constraints on typeclasses like Ord, you had to include the superclass in the instance like so: newtype A f = A (f Int) deriving instance (forall a. Eq a =&gt...
Milliliter asked 27/8, 2021 at 15:51

3

Solved

Consider the following code, which typechecks: module Scratch where import GHC.Exts ensure :: forall c x. c => x -> x ensure = id type Eq2 t = (forall x y. (Eq x, Eq y) => Eq (t x y) ::...
Sky asked 20/7, 2020 at 8:40

0

Why is it that the following code: class TheClass (t :: * -> * -> *) where type TheFamily t :: * -> Constraint data Dict (c :: Constraint) where Dict :: c => Dict c foo :: forall ...
Ooze asked 20/7, 2020 at 6:2

2

I am trying to use this blogpost's approach to higher-kinded data without dangling Identity functors for the trival case together with quantified-constraint deriving: {-# LANGUAGE TypeFamilies #-}...

1

Solved

With quantified constraints I can derive Eq (A f) just fine? However, when I try to derive Ord (A f) it fails. I do not understand how to use quantified constraints when the constraint class has a ...
Kampala asked 14/1, 2020 at 23:20

1

Solved

I'm playing around with a multikinded tagless encoding of Free {-# LANGUAGE PolyKinds #-} {-# LANGUAGE TypeSynonymInstances #-} {-# LANGUAGE TypeFamilies #-} {-# LANGUAGE Rank2Types #-} {-# LANGUA...
Biblio asked 13/6, 2019 at 4:36

3

I'm trying to write something that appears to be analagous to "rank 2 types", but for constraints instead. (Or, maybe it's not correct to assume changing -> in the definition of "rank 2 types" t...
Interlocutrix asked 10/11, 2011 at 6:30
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