openurl Questions

12

Solved

I'm currently developing an App, that needs to open a browser to display a webpage. To do that i use the [UIApplication sharedApplication] openURL method with an url. In iOS 6 this works perfectly...
Klondike asked 14/10, 2013 at 8:46

13

Solved

I have converted the code for making a phone call from Objective-C to Swift, but in Objective-C, we can set the type of the URL that we like to open (e.g. telephone, SMS, web) like this: @"tel:xx"...
Fellowman asked 16/6, 2014 at 19:59

2

Solved

I have this code below import SwiftUI struct MyView: View { let text = "If you want to know more, ***[Click Here](http://example.com)*** to continue" @Environment(\.openURL) private v...
Portillo asked 21/1, 2023 at 11:30

10

Currently with In app purchase the only way to cancel an auto-renewing subscription is to do the following with the device: Settings > Store > View my account > Manage my subscription Is it poss...
Euridice asked 20/3, 2013 at 17:36

2

If locationServicesEnabled() == false, I'm prompting the user to enable their Location Services. The following URL works for 10.0+, redirecting the user to the Settings app and directly to the Loca...
Hitandrun asked 4/9, 2017 at 8:4

5

Solved

We prompt users to upgrade their app if they're running an outdated version. When users tap our update button, I use openURL with an address like itms://itunes.apple.com/us/app/our-app-title/id1234...
Probation asked 8/9, 2015 at 14:14

2

Solved

I integrated Waze into my Swift app, but when I click on the button, Waze opens but nothing happens with the navigation. I juste see the app and that's all, instead of launching the navigation. He...
Oder asked 7/2, 2018 at 10:2

4

I have been attempting to implement a button to open my iOS app from its widget. I realize this issue has been beaten to death on the forums but I cannot find explanation with the specific error I ...
Slobber asked 5/11, 2016 at 15:49

2

Solved

I want to develop an SOS application. When I am trying to use URL schema openURL(), it will display an alert but my requirement is to connect the call without any alert or popup while trying to cal...
Kandykane asked 6/2, 2020 at 11:33

4

Solved

I'm learning flutter web. I'm trying to open another url when button is clicked. Is there any way like this: onclick: ()=>openurl("https://test.com") How can I achieve this? Please help
Playbook asked 9/6, 2019 at 4:43

0

I am trying to open link in Safari browser from inside my iOS app. Its a hybrid app so I made changes in iOS native side (which I am totally unfamiliar with) I have tried this code from below pos...
Popple asked 29/10, 2019 at 17:21

3

Solved

When launching an app from a URL, there is a distinction between whether the URL is freshly launching an app, or if it's resuming an app that has been put into a suspended state. My question is, h...
Townshend asked 29/8, 2013 at 21:29

14

Is it possible to launch any arbitrary iPhone application from within another app?, For example in my application if I want the user to push a button and launch right into the Phone app (close the ...
Plessor asked 7/1, 2009 at 3:41

8

Solved

How to open a URL in the system default browser by using Swift as programming language and OSX as platform? I found a lot with UIApplication like: UIApplication.sharedApplication().openURL(NSURL(st...
Bobbobb asked 2/11, 2014 at 21:49

4

I found solution that I need to add some code in info.plist. I did it like below: <key>LSApplicationQueriesSchemes</key> <array> <string>tel</string> </array> ...
Radiochemistry asked 4/3, 2016 at 9:43

1

Solved

I recently noticed some issues with my app causing a Warning when uploading to the Appstore: Invalid Document Configuration - Document Based Apps should support either the Document Browser (UISup...
Awaken asked 26/9, 2018 at 11:22

8

I´m searching for a opportunity to open a url in java. URL url = new URL("http://maps.google.at/maps?saddr=4714&daddr=Marchtrenk&hl=de"); InputStream is = url.openConnection().getInputStr...
Photina asked 2/4, 2012 at 13:18

8

Solved

So apparently OpenURL has been deprecated in iOS 10. Does anyone have any documentation on why or can explain what to do next? I looked on the Apple site already and found a few things pertaining t...
Thoron asked 15/8, 2016 at 23:1

7

I want to open WIFI setting section from my iOS application, my code was working well before Swift 3 with iOS 9.2 if let settingsURL = URL(string: AppSettingsWifiUrl) { UIApplication.shared.openU...
Beneficiary asked 29/9, 2016 at 7:57

3

So we are creating an iOS app that with the push of a button opens up the device's settings app. I have seen that the method has slightly changed with iOS 10 and Swift 3 so I am using a conditional...
Windham asked 30/9, 2016 at 13:29

6

Solved

I just upgraded from XCode 6.4 to Xcode 7 GM and get started to change the code to be compliant with Swift 2. I could not come over the following errors. The project is a keyboard extension and th...
Gravelly asked 16/9, 2015 at 13:18

2

Solved

i need to open a link in safari browser but i have doubt, which method should i use ? openURL/open or canOpenURL. Can anyone please help me to explain what actual difference between both function? ...
Hedgepeth asked 1/1, 2018 at 9:51

4

I am not even sure how to define the problem but here it goes. I have an application that uses Facebook SDK for user login. I followed the Facebook authorization tutorial. I am not 100% sure how i...
Mimimimic asked 25/4, 2013 at 23:13

5

Solved

I have 2 apps, which are meant for different purpose, where I should not allow user to use both apps in same device. How can I check whether other app installed or not? I think I can do it using O...
Strychnine asked 30/1, 2017 at 12:29

2

Solved

My app freezes after calling openURL on iOS 9.3 builds 13E233 & 13E234. I tried using dispatch_after but that does not fix the issue. Here's the code, nothing special. + (void)someMethod:(UI...
Zahn asked 28/3, 2016 at 7:29

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