mysql-5.5 Questions
17
Solved
I have already seen
http://dev.mysql.com/doc/refman/4.1/en/mysql-config-wizard-file-location.html
How do I find the MySQL my.cnf location
and
http://dev.mysql.com/doc/refman/5.1/en/option-files.htm...
3
Solved
Let's say I have a table, email_phone_notes that looks like this:
+-----------------------+--------------+------+-----+---------+-------+
| Field | Type | Null | Key | Default | Extra |
+----------...
4
Solved
I have got a table time. A time entry (1:n relationship) either belongs to a project entry or to a special_work entry. Either the project id or the special_work id must be set, neither both (exclus...
Bans asked 27/7, 2017 at 11:31
11
Solved
This appears to be a common problem on 12.04. I've tried everthing in this thread including:
sudo apt-get clean
sudo apt-get autoclean
sudo apt-get remove --purge mysql-client-5.5 mysql-client-c...
Salacious asked 7/11, 2012 at 18:43
2
Solved
Is it possible to set or initialize a query in MySQL for every new connection ?
Whenever a connection is created, it will call a procedure or a select query automatically ?
Any script or config o...
3
Solved
I have large number of open files limit in MySQL.
I have set open_files_limit to 150000 but still MySQL uses almost 80% of it.
Also I have low traffic and max concurrent connections around 30 and...
2
Solved
I want to check if innodb_file_per_table is set (i.e .ibd is created) for each database tables using MYSQL-5.5 query.
Any way to do it?
Studer asked 26/3, 2014 at 4:43
1
Solved
I have installed mysql55-server using macports.
I can start the server successfully via:
$ sudo launchctl load -w /Library/LaunchDaemons/org.macports.mysql55-server.plist
And confirm I am runni...
Bobine asked 23/10, 2014 at 21:53
1
Solved
I just saw that MySQL 5.5 offers utf8_general_mysql500_ci as collation.
What is the difference to other collations like utf8_general_ci?
Should I better use utf8_general_mysql500_ci?
2
select
disease_name
from
disease
where
disease_id=
(select disease_id from disease_symptom where
disease.disease_id=disease_symptom.disease_id AND
symptom_id=
(select symptom_id from s...
1
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