forced-unwrapping Questions
23
Solved
The Swift Programming Language guide has the following example:
class Person {
let name: String
init(name: String) { self.name = name }
var apartment: Apartment?
deinit { println("\(name) is ...
Alfy asked 3/6, 2014 at 14:52
4
Solved
I was very confused about forced unwrapping and implicit unwrapping at first. Now, the following understanding comes from my self-study:
There is no action available for implicit unwrapping, but t...
Gunar asked 7/8, 2016 at 18:59
3
Solved
I've been playing around with Swift and discovered that when down casting an object to be inserted into a dictionary, I get a weird warning: Treating a forced downcast to 'String' as optional will ...
Phosphate asked 14/6, 2014 at 19:38
5
Solved
When I am about to fire my segue for the 2nd view I also send some values like this:
if let aTime = ads[indexPath.row]["unix_t"].int {
toView.time = aTime
}
if let aTitle = ads[indexPath.row]["t...
Parlour asked 27/6, 2016 at 18:53
1
Is there a way (via a compiler flag or a script) to detect forced unwraps across a Swift project?
I'm thinking about stuff like these:
let b = a as! B
let c = a!
a!.method()
Without triggering ...
Galactometer asked 12/12, 2015 at 2:57
1
Solved
Is there a good way to access a Option Value inside a Option Object?
The nested match cases result in a ugly tree structure.
So if I have for example:
case class MyObject(value: Option[Int])
val ...
Saltwort asked 7/3, 2015 at 9:13
1
I'm used to write code with early return/golden path in Objective-C. I tried this approach in Swift, and noticed that early return comes at the expense of using the forced unwrapping operator (!) w...
Crate asked 25/8, 2014 at 11:17
2
Solved
In swift documentation, you can find this :
if convertedNumber != nil {
println("convertedNumber has an integer value of \(convertedNumber!).")
}
// prints "convertedNumber has an integer value o...
Byelection asked 15/8, 2014 at 10:16
1
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