Debugging some code in Visual Studio 2008 (C++), I noticed that the address in my function pointer variable is not the actual address of the function itself. This is an extern "C" function.
int main() {
void (*printaddr)(const char *) = &print; // debug shows printaddr == 0x013C1429
}
Address: 0x013C4F10
void print() {
...
}
The disassembly of taking the function address is:
void (*printaddr)(const char *) = &print;
013C7465 C7 45 BC 29 14 3C 01 mov dword ptr [printaddr],offset print (13C1429h)
EDIT: I viewed the code at address 013C4F10 and the compiler is apparently inserting a "jmp" instruction at that address.
013C4F10 E9 C7 3F 00 00 jmp print (013C1429h)
There is actually a whole jump table of every method in the .exe.
Can someone expound on why it does this? Is it a debugging "feature" ?
print
is0x013C4F10
? Looking at the disassembly it seems like the address of print is indeed0x013C1429
and that's the value being stored inprintaddr
– Fetid