Split decimal variable into integral and fraction parts

Question

I am trying to extract the integral and fractional parts from a decimal value (both parts should be integers):

decimal decimalValue = 12.34m;
int integral = (int) decimal.Truncate(decimalValue);
int fraction = (int) ((decimalValue - decimal.Truncate(decimalValue)) * 100);

(for my purpose, decimal variables will contain up to 2 decimal places)

Are there any better ways to achieve this?

Haddix

A better approach may be not to use a decimal at all, but use an int/long representing "your value multipled by 100". – Elseelset

Beware of unusual values. The max value for a decimal is ~7.9e28. The max value for an int is ~2e9 (significantly smaller). Even long only goes to ~9e18. So if you know the value will always be >= 0 you can use a ulong which goes all the way to ~18e18, giving a bit more leeway. – Carolyncarolyne

Following answer of a similar question may suits those needs for fractional part: https://mcmap.net/q/187925/-get-the-decimal-part-from-a-double – Friedafriedberg

Answer 1

       decimal fraction = (decimal)2.78;
        int iPart = (int)fraction;
        decimal dPart = fraction % 1.0m;

Stupor

Very good use of modulus operator on decimal. I did not expect this to work, but it does beautifully (and it's fast) :) – Molliemollify

I second @GoneCoding but the OP mentions "both parts should be integers". – Intisar

@GeroldBroserreinstatesMonica Regarding the dPart variable, you can simply cast it as integer. – Ginger

Not working if integer part is bigger that Int32.MaxValue – Trigeminal

Answer 2

Try mathematical definition:

var fraction = (int)(100.0m * (decimalValue - Math.Floor(decimalValue)));

Although, it is not better performance-wise but at least it works for negative numbers.

Aspectual

Try to use this: var FileMinorPartClient = (int)(100.0m * (clientFileVersion - Math.Floor(clientFileVersion))); I get: "Operator '*' cannot be applied to operands of type 'decimal' and 'double'" (clientFileVersion is a double, a la 1.4) – Articular

@B.ClayShannon It says so because you cannot mix those two. Either change 100.0m to 100.0 or make sure decimalValue is of decimal type – Aspectual

Answer 3

decimal fraction = doubleNumber - Math.Floor(doubleNumber) 

or something like that.

Tacye

Answer 4

How about:

int fraction = (int) ((decimalValue - integral) * 100);

Emmett

Answer 5

For taking out fraction you can use this solution:

Math.ceil(((f < 1.0) ? f : (f % Math.floor(f))) * 10000)

Proposal