I have a floating point number:
var f = 0.1457;
Or:
var f = 4.7005
How do I get just the fraction remainder as integer?
I.e. in the first example I want to get:
var remainder = 1457;
In the second example:
var remainder = 7005;
I have a floating point number:
var f = 0.1457;
Or:
var f = 4.7005
How do I get just the fraction remainder as integer?
I.e. in the first example I want to get:
var remainder = 1457;
In the second example:
var remainder = 7005;
This will do it (up to the 4 digits that you want, change the multipler (10000) to larger or smaller if you want smaller or larger number):
Math.ceil(((f < 1.0) ? f : (f % Math.floor(f))) * 10000)
f % Math.floor(f)
is the same as f % 1
except the latter also works on negative numbers –
Neom function frac(f) {
return f % 1;
}
%
is the modulo operation, and the remainder of any number divided by one is the fractional component of that number. –
Suitable While this is not what most people will want, but TS asked for fract as integer, here it is:
function fract(n){ return Number(String(n).split('.')[1] || 0); }
fract(1.23) // = 23
fract(123) // = 0
fract(0.0008) // = 8
This will do it (up to the 4 digits that you want, change the multipler (10000) to larger or smaller if you want smaller or larger number):
Math.ceil(((f < 1.0) ? f : (f % Math.floor(f))) * 10000)
f % Math.floor(f)
is the same as f % 1
except the latter also works on negative numbers –
Neom I would argue that, assuming we want to display these values to the user, treating these numbers as strings would be the best approach. This gets round the issue of fractional values such as 0.002.
I came accross this issue when trying to display prices with the cents in superscript.
let price = 23.43; // 23.43
let strPrice = price.toFixed(2) + ''; // "23.43"
let integer = strPrice.split(".")[0] // "23"
let fractional = strPrice.split(".")[1] // "43"
parseInt(parseFloat(amount).toString().split('.')[1], 10)
NaN
for integers, instead of 0. –
Kosiur You can subtract the floor of the number, giving you just the fractional part, and then multiply by 10000, i.e.:
var remainder = (f-Math.floor(f))*10000;
This also depends on what you want to do with the remainder (as commenters already asked). For instance, if the base number is 1.03, do you want the returned remainder as 3 or 03 -- I mean, do you want it as a number or as a string (for purposes of displaying it to the user). One example would be article price display, where you don't want to conver 03 to 3 (for instance $1.03) where you want to superscript 03.
Next, the problem is with float precision. Consider this:
var price = 1.03;
var frac = (price - Math.floor(price))*100;
// frac = 3.0000000000000027
So you can "solve" this by slicing the string representation without multiplication (and optional zero-padding) in such cases. At the same time, you avoid floating precision issue. Also demonstrated in this jsfiddle.
This post about floating precision might help as well as this one.
var strNumber = f.toString();
var remainder = strNumber.substr(strNumber.indexOf('.') + 1, 4);
remainder = Number(reminder);
Similar method to Martina's answer with a basic modulo operation but solves some of the issues in the comments by returning the same number of decimal places as passed in.
Modifies a method from an answer to a different question on SO which handles the scientific notation for small floats.
Additionally allows the fractional part to be returned as an integer (ie OP's request).
function sfract(n, toInt) {
toInt = false || toInt;
let dec = n.toString().split('e-');
let places = dec.length > 1
? parseInt(dec[1], 10)
: Math.floor(n) !== n ? dec[0].split('.')[1].length : 0;
let fract = parseFloat((n%1).toFixed(places));
return toInt ? fract * Math.pow(10,places) : fract;
};
function sfract(n, toInt) {
toInt = false || toInt;
let dec = n.toString().split('e-');
let places = dec.length > 1
? parseInt(dec[1], 10)
: Math.floor(n) !== n ? dec[0].split('.')[1].length : 0;
let fract = parseFloat((n%1).toFixed(places));
return toInt ? fract * Math.pow(10,places) : fract;
};
console.log(sfract(0.0000005)); // 5e-7
console.log(sfract(0.0000005, true)); // 5
console.log(sfract(4444)); // 0
console.log(sfract(4444, true)); // 0
console.log(sfract(44444.0000005)); // 5e-7
console.log(sfract(44444.00052121, true)); // 52121
console.log(sfract(34.5697)); // 0.5697
console.log(sfract(730.4583333333321, true)); // 4583333333321
function fractionAsStr(num)
{
num += '';
let i = num.indexOf('.');
return (i == -1) ?
'' : num.substr(i + 1);
}
let numbers = [-2, -1.3768587,
0, 0.04555, .000555,
1, 2.3445534];
for (let num of numbers)
console.log(
`${num} ➞ '${fractionAsStr(num)}'`);
/*
Output:
"-2 ➞ ''"
"-1.3768587 ➞ '3768587'"
"0 ➞ ''"
"0.04555 ➞ '04555'"
"0.000555 ➞ '000555'"
"1 ➞ ''"
"2.3445534 ➞ '3445534'"
*/
@Udara Seneviratne
const findFraction = (num) => {
return parseInt( // 5.---------------- And finally we parses a "string" type and returns an integer
// 1. We convert our parameter "num" to the "string" type (to work as with an array in the next step)
// result: "1.012312"
num.toString()
// 2. Here we separating the string as an array using the separator: " . "
// result: ["1", "012312"]
// https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/split
.split('.')
// 3. With help a method "Array.splice" we cut the first element of our array
// result: ["012312"]
// https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/splice
.splice(1.1)
// 4. With help a method "Array.shift" we remove the first element from an array and returns that
// result: 012312 (But it's still the "string" type)
// https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/shift
.shift()
)
}
// Try it
console.log("Result is = " + findFraction (1.012312))
// Type of result
console.log("Type of result = " + typeof findFraction (1.012312))
// Some later operation
console.log("Result + some number is = " + findFraction (1.012312) + 555)
.splice(1, 1)
(comma instead of dot) and (findFraction (1.012312) + 555)
(brackets around this expression so that it is added and not appended)? –
Smilax © 2022 - 2024 — McMap. All rights reserved.
var f = 0.0145;
?145
or0145
? – Establishment1.156479
to give156479
and2.12
to give12
? Is this purely for display purposes? In which case you probably don't want to approach this mathematically. In the examples I give the 1st dp is different in significance by 100000. Or will you always be working to 4dp? – Greenwich