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Python: Post Request with image files
Asked Answered
pythonpostrequesturllib2urllib
G

1

6

I have a server and I am trying to build a post request to get the data back. I think one way to achieve this is to add the parameters in the header and make the request. But I am getting few errors that I don't understand well enough to go forward.

Html Form

<html>
<head>
<meta http-equiv="content-type" content="text/html; charset=ISO-8859-1">
  </head>
  <body>
     <form method="POST" action="http://some.server.com:61235/imgdigest" enctype="multipart/form-data">
        quality:<input type="text" name="quality" value="2"><br>
        category:<input type="text" name="category" value="1"><br>
        debug:<input type="text" name="debug" value="1"><br>
        image:<input type="file" name="image"><br>
        <input type="submit" value="Submit">
     </form>
  </body>
</html>

Python code: I have edited the question based on the answer

import urllib, urllib2
import base64

if __name__ == '__main__':
    page = 'http://some.site.com:61235/'
    with open("~/image.jpg", "rb") as image_file:
        encoded_image = base64.b64encode(image_file.read())
    raw_params = {'quality':'2','category':'1','debug':'0', 'image': encoded_image}
    params = urllib.urlencode(raw_params)
    request = urllib2.Request(page, params)
    request.add_header("Content-type", "application/x-www-form-urlencoded; charset=UTF-8")
    page = urllib2.urlopen(request)
    info = page.info()

Errors:

    page = urllib2.urlopen(request)
  File "/opt/local/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 126, in urlopen
    return _opener.open(url, data, timeout)
  File "/opt/local/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 406, in open
    response = meth(req, response)
  File "/opt/local/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 519, in http_response
    'http', request, response, code, msg, hdrs)
  File "/opt/local/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 444, in error
    return self._call_chain(*args)
  File "/opt/local/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 378, in _call_chain
    result = func(*args)
  File "/opt/local/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 527, in http_error_default
    raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
urllib2.HTTPError: HTTP Error 404: Not Found
Goar answered 18/7, 2012 at 22:23 Comment(1)
Well, for one thing, the image needs to be an image, not a string. I would suggest trying out requests, instead of using urllib, urllib2. docs.python-requests.org/en/latest/index.html – Ambroseambrosi
E
5

Add a this header:

request.add_header("Content-type", "application/x-www-form-urlencoded; charset=UTF-8")

Also, the image parameter you're sending is a string, not the contents of the image file. You need to b64 encode it

import base64

with open("image.jpg", "rb") as image_file:
    encoded_image = base64.b64encode(image_file.read())

then use encoded_image instead of '~/image.jpg' in raw_params

Errantry answered 19/7, 2012 at 20:53 Comment(3)
So I should add it to the header after request = urllib2.Request(page, params)? – Goar
make sure the url you're using in your python code is exactly the same as action attribute in the html form. Looks like you're adding '.html' in python. – Errantry
ok, but notice how the url is still not the same, in python you have: page = 'some.site.com:61235' and in html you have: ...<form method="POST" action="some.server.com:61235/imgdigest"... Python is missing the /imgdigest part – Errantry

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