urllib Questions
2
Solved
Original URL ▶ https://www.exeam.org/index.html
I want to extract exeam.org/ or exeam.org from original URL.
To do this, I used urllib the most powerful parser in Python that I know,
but unfortunat...
8
Solved
I am trying to open an https URL using the urlopen method in Python 3's urllib.request module. It seems to work fine, but the documentation warns that "[i]f neither cafile nor capath is specified, ...
Parlour asked 23/6, 2014 at 20:4
3
Solved
When doing a simple request, on python (Entought Canopy to be precise), with urllib2, the server denies me access :
data = urllib.urlopen(an url i cannot post because of reputation, params)
print...
Hereupon asked 23/7, 2014 at 14:47
6
Solved
In my project I'm handling all HTTP requests with python requests library.
Now, I need to query the http server using specific DNS - there are two environments, each using its own DNS, and changes...
Navarro asked 24/3, 2014 at 12:28
4
Solved
I have some troubles with getting the data from the website. The website source is here:
view-source:http://release24.pl/wpis/23714/%22La+mer+a+boire%22+%282011%29+FRENCH.DVDRip.XviD-AYMO
there...
Yogh asked 27/6, 2012 at 20:48
4
Solved
I am trying to write a program that will download mp3's off of a website then join them together but whenever I try to download the files I get this error:
Traceback (most recent call last):
File ...
Faroff asked 31/7, 2013 at 3:13
12
Solved
I'm trying to scrape a website, but it gives me an error.
I'm using the following code:
import urllib.request
from bs4 import BeautifulSoup
get = urllib.request.urlopen("https://www.website.c...
Trost asked 23/11, 2014 at 18:47
4
Python beginner here. I want to be able to timeout my download of a video file if the process takes longer than 500 seconds.
import urllib
try:
urllib.urlretrieve ("http://www.videoURL.mp4", "fi...
5
Solved
OS: Windows 7; Python 2.7.3 using the Python GUI Shell
I'm trying to read a website through Python, and several authors use the urllib and urllib2 libraries. To store the site in a variable, I've ...
31
Solved
I have a small utility that I use to download an MP3 file from a website on a schedule and then builds/updates a podcast XML file which I've added to iTunes.
The text processing that creates/updat...
5
Solved
How can I set proxy for the last urllib in Python 3.
I am doing the next
from urllib import request as urlrequest
ask = urlrequest.Request(url) # note that here Request has R not r as prev version...
2
Solved
I have this line of code: urllib.request.urlretrieve('http://lolupdater.com/downloads/LPB.exe', 'LPBtest.exe'), but when I run it, it throws an error urllib.error.HTTPError: HTTP Error 403: Forbidd...
Whitewash asked 27/7, 2017 at 18:9
10
Im running a python script on aws lambda and its throwing the following error.
{
"errorMessage": "Unable to import module 'app': urllib3 v2.0 only supports OpenSSL 1.1.1+, currentl...
Caco asked 6/5, 2023 at 15:53
48
Solved
I am getting the following error:
Exception in thread Thread-3:
Traceback (most recent call last):
File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/threading.py", lin...
Amongst asked 8/1, 2015 at 8:14
4
Background: I am using urllib.urlretrieve, as opposed to any other function in the urllib* modules, because of the hook function support (see reporthook below) .. which is used to display a textual...
10
please excuse me for my ugly english ;-)
Imagine this very simple model :
class Photo(models.Model):
image = models.ImageField('Label', upload_to='path/')
I would like to create a Photo from a...
Pragmatics asked 8/9, 2009 at 10:29
8
I get InvalidURL: URL can't contain control characters when I try to send a request using urllib
I am trying to get a JSON response from the link used as a parameter to the urllib request. but it gives me an error that it can't contain control characters.
how can I solve the issue?
start_url =...
Progress asked 25/10, 2020 at 7:8
3
Solved
I'm trying to open and parse a html page. In python 2.7.8 I have no problem:
import urllib
url = "https://ipdb.at/ip/66.196.116.112"
html = urllib.urlopen(url).read()
and everything is fine. How...
Imam asked 8/2, 2015 at 15:57
10
I have tried
import urllib.request
or
import urllib
The path for my urllib is
/Library/Frameworks/Python.framework/Versions/3.5/lib/python3.5/urllib/__init__.py
I am wondering where is ur...
Percival asked 5/5, 2016 at 4:5
4
Solved
This is my first work with web scraping. So far I am able to navigate and find the part of the HTML I want. I can print it as well. The problem is printing only the text, which will not work. I get...
Soukup asked 24/2, 2014 at 19:51
6
Hello I am trying to learn web scraping. I installed Anaconda3 in Windows 10. Conda version 4.5.12. Python version 3.7.1.
I wrote following script which produces the mentioned error.
import bs4
f...
Enfeeble asked 28/2, 2019 at 13:2
5
I have the following code :
import urllib.request
try:
url = "https://www.google.com/search?q=test"
headers = {}
usag = 'Mozilla/5.0 (Macintosh; Intel Mac OS X 10.6; rv:25.0) Gecko/20100101 F...
Grubb asked 28/1, 2016 at 19:48
7
I would like to import urllib to use the function 'request'. However, I encountered an error when trying to do so. I tried pip install urllib but still had the same error. I am using Python 3.6. Re...
Fortyfour asked 9/12, 2017 at 15:46
5
Solved
I have seen this thread already - How can I unshorten a URL?
My issue with the resolved answer (that is using the unshort.me API) is that I am focusing on unshortening youtube links. Since unshort...
3
Solved
In python 2, it was possible to get debug output from urllib by doing
import httplib
import urllib
httplib.HTTPConnection.debuglevel = 1
response = urllib.urlopen('http://example.com').read()
Ho...
Promiscuous asked 25/4, 2009 at 22:31
1 Next >
© 2022 - 2024 — McMap. All rights reserved.