java.text.parseException: Unparseable date : 2020-02-06T08:00:00

Question

Getting parse exception when I'm applying a particular format to the date.

SimpleDateFormat df = new SimpleDateFormat("hh:mm a");
try {
    String s=timeSlotsArrayList.get(position).getScheduledStartTime();
    Date d = df.parse(s);
    times.setText(df.format(d));
}
catch (ParseException e) {
    e.printStackTrace();
}

AM is getting instead of PM issue image

Siren

How did you format df? – Nardoo

Updated the code @Md.Asaduzzaman – Siren

Are those two different issues? How can you get any AM or PM in the image when you get a parse exception first? – Plast

As an aside consider throwing away the long outmoded and notoriously troublesome SimpleDateFormat and friends, and adding ThreeTenABP to your Android project in order to use java.time, the modern Java date and time API. It is so much nicer to work with. – Plast

Does this answer your (first) question? Converting String to Date using SimpleDateFormat is returning random date [duplicate]. Maybe in conjunction with this? Date format conversion Android. – Plast

Does this answer your question? What is this date format? 2011-08-12T20:17:46.384Z – Myelencephalon

Answer 1

You didn't apply correct format to your SimpleDateFormat. Use

SimpleDateFormat df = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss");

And then parse time like below:

Date d = df.parse(s);

String time = new SimpleDateFormat("hh:mm a").format(d);
times.setText(time);

Nardoo

I need only time from the string,No need date – Siren

Worked but 12:30 is getting AM instead of PM. I added image below of my code. – Siren

Use HH:mm:ss instead of hh:mm:ss for 24 hour format – Nardoo

I got another issue related to the date. I want to reduce one day for particular date. But It's reducing for 1 month. df = new SimpleDateFormat("EEEE, dd MMMM YYYY"); Date prevDate = df.parse(dateText.getText().toString()); Calendar c = Calendar.getInstance(); c.setTime(prevDate); c.add(Calendar.DAY_OF_YEAR, -1); Date d=c.getTime(); dateText.setText(df.format(d)); – Siren