Python: Get HTTP headers from urllib2.urlopen call?
Asked Answered
T

6

51

Does urllib2 fetch the whole page when a urlopen call is made?

I'd like to just read the HTTP response header without getting the page. It looks like urllib2 opens the HTTP connection and then subsequently gets the actual HTML page... or does it just start buffering the page with the urlopen call?

import urllib2
myurl = 'http://www.kidsidebyside.org/2009/05/come-and-draw-the-circle-of-unity-with-us/'
page = urllib2.urlopen(myurl) // open connection, get headers

html = page.readlines()  // stream page
Talley answered 9/5, 2009 at 14:11 Comment(0)
C
52

Use the response.info() method to get the headers.

From the urllib2 docs:

urllib2.urlopen(url[, data][, timeout])

...

This function returns a file-like object with two additional methods:

  • geturl() — return the URL of the resource retrieved, commonly used to determine if a redirect was followed
  • info() — return the meta-information of the page, such as headers, in the form of an httplib.HTTPMessage instance (see Quick Reference to HTTP Headers)

So, for your example, try stepping through the result of response.info().headers for what you're looking for.

Note the major caveat to using httplib.HTTPMessage is documented in python issue 4773.

Cerebrum answered 29/10, 2009 at 0:17 Comment(5)
Python 3 Note First, there is nothing like response.info().headers, do a dict(response.info()). Second, for the HTTP status code do response.status.Tiler
Does this only gets the header or only prints the header?Stack
Where is headers documented? Also consider using response.info().items() that returns a key value dict.Conference
Python 2 Note this is what you want: response.info().getheader('Content-Type') source: #1654091Harrod
actually for Python 3: response.headers will do, for more info http.client.HTTPResponseCourtnay
I
42

What about sending a HEAD request instead of a normal GET request. The following snipped (copied from a similar question) does exactly that.

>>> import httplib
>>> conn = httplib.HTTPConnection("www.google.com")
>>> conn.request("HEAD", "/index.html")
>>> res = conn.getresponse()
>>> print res.status, res.reason
200 OK
>>> print res.getheaders()
[('content-length', '0'), ('expires', '-1'), ('server', 'gws'), ('cache-control', 'private, max-age=0'), ('date', 'Sat, 20 Sep 2008 06:43:36 GMT'), ('content-type', 'text/html; charset=ISO-8859-1')]
Impeller answered 9/5, 2009 at 14:17 Comment(0)
D
23

Actually, it appears that urllib2 can do an HTTP HEAD request.

The question that @reto linked to, above, shows how to get urllib2 to do a HEAD request.

Here's my take on it:

import urllib2

# Derive from Request class and override get_method to allow a HEAD request.
class HeadRequest(urllib2.Request):
    def get_method(self):
        return "HEAD"

myurl = 'http://bit.ly/doFeT'
request = HeadRequest(myurl)

try:
    response = urllib2.urlopen(request)
    response_headers = response.info()

    # This will just display all the dictionary key-value pairs.  Replace this
    # line with something useful.
    response_headers.dict

except urllib2.HTTPError, e:
    # Prints the HTTP Status code of the response but only if there was a 
    # problem.
    print ("Error code: %s" % e.code)

If you check this with something like the Wireshark network protocol analazer, you can see that it is actually sending out a HEAD request, rather than a GET.

This is the HTTP request and response from the code above, as captured by Wireshark:

HEAD /doFeT HTTP/1.1
Accept-Encoding: identity
Host: bit.ly
Connection: close
User-Agent: Python-urllib/2.7

HTTP/1.1 301 Moved
Server: nginx
Date: Sun, 19 Feb 2012 13:20:56 GMT
Content-Type: text/html; charset=utf-8
Cache-control: private; max-age=90
Location: http://www.kidsidebyside.org/?p=445
MIME-Version: 1.0
Content-Length: 127
Connection: close
Set-Cookie: _bit=4f40f738-00153-02ed0-421cf10a;domain=.bit.ly;expires=Fri Aug 17 13:20:56 2012;path=/; HttpOnly

However, as mentioned in one of the comments in the other question, if the URL in question includes a redirect then urllib2 will do a GET request to the destination, not a HEAD. This could be a major shortcoming, if you really wanted to only make HEAD requests.

The request above involves a redirect. Here is request to the destination, as captured by Wireshark:

GET /2009/05/come-and-draw-the-circle-of-unity-with-us/ HTTP/1.1
Accept-Encoding: identity
Host: www.kidsidebyside.org
Connection: close
User-Agent: Python-urllib/2.7

An alternative to using urllib2 is to use Joe Gregorio's httplib2 library:

import httplib2

url = "http://bit.ly/doFeT"
http_interface = httplib2.Http()

try:
    response, content = http_interface.request(url, method="HEAD")
    print ("Response status: %d - %s" % (response.status, response.reason))

    # This will just display all the dictionary key-value pairs.  Replace this
    # line with something useful.
    response.__dict__

except httplib2.ServerNotFoundError, e:
    print (e.message)

This has the advantage of using HEAD requests for both the initial HTTP request and the redirected request to the destination URL.

Here's the first request:

HEAD /doFeT HTTP/1.1
Host: bit.ly
accept-encoding: gzip, deflate
user-agent: Python-httplib2/0.7.2 (gzip)

Here's the second request, to the destination:

HEAD /2009/05/come-and-draw-the-circle-of-unity-with-us/ HTTP/1.1
Host: www.kidsidebyside.org
accept-encoding: gzip, deflate
user-agent: Python-httplib2/0.7.2 (gzip)

Deliadelian answered 19/2, 2012 at 14:27 Comment(1)
I missed it the first time I read the answer, but response.info().dict is exactly what I was looking for. This is not explained in the docs.Acnode
B
8

urllib2.urlopen does an HTTP GET (or POST if you supply a data argument), not an HTTP HEAD (if it did the latter, you couldn't do readlines or other accesses to the page body, of course).

Billibilliard answered 9/5, 2009 at 14:18 Comment(0)
R
4

One-liner:

$ python -c "import urllib2; print urllib2.build_opener(urllib2.HTTPHandler(debuglevel=1)).open(urllib2.Request('http://google.com'))"
Receivership answered 30/3, 2012 at 8:11 Comment(0)
B
-1
def _GetHtmlPage(self, addr):
  headers = { 'User-Agent' : self.userAgent,
            '  Cookie' : self.cookies}

  req = urllib2.Request(addr)
  response = urllib2.urlopen(req)

  print "ResponseInfo="
  print response.info()

  resultsHtml = unicode(response.read(), self.encoding)
  return resultsHtml  
Bellhop answered 28/7, 2014 at 9:25 Comment(0)

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