-​->-​- operator in Java

Question

I was wondering, what does the -->-- operator do in Java?

For example, if I have the following code:

int x = 3;
int y = 3;
if (x -->-- y) {
    return true;
}

This always returns true.

Thank you!

Edible

#1642528 – Horselaugh

Related to, but not a duplicate of the question #1642528 because that is a C++ program. – Hoick

I think OP may want to edit the question to acknowledge the pseudo-dupe, and reword accordingly to differences between Java and C++. If there are no differences, then the question may be low quality. No offense. – Affecting

@toy just read the notice. – Joyejoyful

Answer 1

In Java, -->-- is not actually an operator.

What you wrote is actually if ((x--) > (--y)).

And, as we know from this answer, the --y is predecrement, while the x-- is postdecrement, so therefore, this is basically if (3 > 2), which always returns true.

Heteropolar

This is probably a very tricky homework problem. Very interesting! – Goldthread

Answer 2

Positcrement and preicrement are very similar operators. Java's bytecode gives a better understanding. Each of them consists of two operations. Load variable and increment it. The only difference is in the order of this operations. If statement from your case is compiled this way:

 4: iload_1               //load x
 5: iinc          1, -1   //decrement x
 8: iinc          2, -1   //decrement y
11: iload_2               //load y
12: if_icmple     23      //check two values on the stack, if true go to 23rd instruction

When JVM comes up to an if statement it has 3 and 2 on the stack. Line 4 and 5 are compiled from x--. Lines 8 and 11 from --y. x is loaded before increment and y after.

BTW, it's strange that javac does not optimize out this static expression.

Dendroid