urllib Questions

1

Solved

I am programming a software in Python to download HTTP PDF from a database. Sometimes the download stop with this message : retrieval incomplete: got only 3617232 out of 10689634 bytes How can ...
Hollow asked 7/1, 2010 at 15:46

1

import urllib print urllib.urlopen('http://www.reefgeek.com/equipment/Controllers_&_Monitors/Neptune_Systems_AquaController/Apex_Controller_&_Accessories/').read() The above script works...
Tralee asked 22/12, 2009 at 15:34

1

Solved

Gmail has this sweet thing going on to get an atom feed: def gmail_url(user, pwd): return "https://"+str(user)+":"+str(pwd)+"@gmail.google.com/gmail/feed/atom" Now when you do this in a browser...
Cirillo asked 21/11, 2009 at 23:1

4

Solved

Writing a python program, and I came up with this error while using the urllib.urlopen function. Traceback (most recent call last): File "ChurchScraper.py", line 58, in <module> html = GetAl...
Scintillometer asked 2/11, 2009 at 12:14

7

Solved

Problem When screen-scraping a webpage using python one has to know the character encoding of the page. If you get the character encoding wrong than your output will be messed up. People usually ...
Vicegerent asked 30/9, 2009 at 0:41

3

Solved

I had expected this to work: >>> import urllib.request as r >>> import zlib >>> r.urlopen( r.Request("http://google.com/search?q=foo", headers={"User-Agent": "Mozilla/5....
Vorfeld asked 6/4, 2009 at 4:24

3

When I run this: import urllib feed = urllib.urlopen("http://www.yahoo.com") print feed I get this output in the interactive window (PythonWin): <addinfourl at 48213968 whose fp = <sock...
Friesen asked 1/3, 2009 at 19:56

4

Solved

I have a simple website I'm testing. It's running on localhost and I can access it in my web browser. The index page is simply the word "running". urllib.urlopen will successfully read the page but...
Misalliance asked 14/10, 2008 at 14:57

2

Solved

(ClientCookie is a module for (automatic) cookie-handling: http://wwwsearch.sourceforge.net/ClientCookie) # I encode the data I'll be sending: data = urllib.urlencode({'username': 'mandark', 'pass...
Jidda asked 22/9, 2008 at 1:28

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