trivially-copyable Questions
1
Solved
Consider the following move-only type:
struct MoveOnly
{
MoveOnly() = default;
~MoveOnly() = default;
MoveOnly(const MoveOnly&) = delete;
MoveOnly& operator=(const MoveOnly&) = del...
Campania asked 18/8, 2024 at 16:50
3
Solved
The following code prints whether std::atomic<bool> is trivially copyable:
#include <atomic>
#include <iostream>
#include <type_traits>
int main(){
std::cout << std:...
Seizing asked 25/4, 2024 at 13:13
2
Solved
Example code could be found below or on godbolt. Say we have 4 classes:
S<T>: holding a data member.
SCtor<T>: holding a data member and has a template constructor.
SCtorMutable<T...
Craniotomy asked 28/6, 2023 at 10:4
3
Solved
Code is like:
#include <iostream>
#include <type_traits>
class A
{
A() = default;
A(const A&) = default;
A(A&&) = default;
A& operator=(const A&) = defaul...
Gatling asked 13/2, 2023 at 8:53
3
Solved
The standard says
A trivially copyable class is a class:
(1.1) that has at least one eligible copy constructor, move
constructor, copy assignment operator, or move assignment operator
([special], ...
Roundtree asked 18/7, 2022 at 13:28
1
A class with all special functions defaulted except a non-trivial destructor is not trivially move or copy constructible. See https://godbolt.org/z/o83rPz for an example:
#include <type_traits&g...
Volauvent asked 16/9, 2020 at 14:30
1
Solved
std::is_pod has been deprecated in C++20.
What's the reason for this choice? What should I use in place of std::is_pod to know if a type is actually a POD?
Unrivalled asked 12/1, 2018 at 11:46
1
Solved
With the introduction of c++11, trivially copyableness has gotten quite relevant. Most notably in the use of 'std::atomic'. The basics are quite simple. A class foo is trivially copyable if:
foo* ...
Crispas asked 7/5, 2015 at 9:24
1
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