stopiteration Questions

7

Solved

I am trying to run this code in Python 3.7: import web urls = ('/', 'index') if __name__ == "__main__": app = web.application(urls, globals()) app.run() But it gives me this error ev...
Aeroballistics asked 6/8, 2018 at 5:19

3

Solved

i have a generator where i would like to add an initial and final value to the actual content, it's something like this: # any generic queue where i would like to get something from q = Queue() d...
Marney asked 22/7, 2011 at 2:1

5

Solved

Why in the example function terminates: def func(iterable): while True: val = next(iterable) yield val but if I take off yield statement function will raise StopIteration exception? EDIT: So...
Industrialist asked 9/5, 2013 at 15:20

1

Solved

I'm reading the documentation for Python 3 here: If a generator code directly or indirectly raises StopIteration, it is converted into a RuntimeError (retaining the StopIteration as the new exce...
Innocent asked 6/8, 2018 at 16:32

1

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I am not able to clarify my self over the use of next() in python(3). I have a data : chr pos ms01e_PI ms01e_PG_al ms02g_PI ms02g_PG_al ms03g_PI ms03g_PG_al ms04h_PI ms04h_PG_al 2 15881989 4 C|C ...
Inurn asked 10/1, 2018 at 4:14

1

Solved

Could someone help me understand what PEP479 is about? I was reading the doc and couldn't get my head around it. The abstract says: This PEP proposes a change to generators: when StopIteration ...
Interlocutress asked 8/6, 2016 at 15:45

3

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I'm curious about the difference between using raise StopIteration and a return statement in generators. For example, is there any difference between these two functions? def my_generator0(n): f...
Fury asked 6/1, 2013 at 15:52

4

Solved

There are several ways to break out of a few nested loops They are: 1) to use break-continue for x in xrange(10): for y in xrange(10): print x*y if x*y > 50: break else: continue # only...
Regurgitate asked 3/8, 2011 at 0:5

1

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I have a line that is pulling in variables from multiple lists and I want it to avoid the StopIteration error that comes up so that it can move onto the next line. At the moment I am using the brea...
Boulevardier asked 26/6, 2013 at 10:43

1

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In this piece of code, why does using for result in no StopIteration or is the for loop trapping all exceptions and then silently exiting? In which case, why do we have the extraneous return?? Or i...
Sapor asked 19/1, 2013 at 11:44

1

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I am trying to iterate through a list, and I need to perform specific operation when and only when the iteration reached the end of the list, see example below: data = [1, 2, 3] data_iter = data....
Acanthus asked 5/7, 2012 at 20:28

4

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What would be the nice way to return something from an iterator one last time when it's exhausted. I'm using a flag, but this is rather ugly: class Example(): def __iter__(self): self.lst = [1,...
Saudra asked 22/2, 2012 at 18:47

2

Solved

I am using generators to perform searches in lists like this simple example: >>> a = [1,2,3,4] >>> (i for i, v in enumerate(a) if v == 4).next() 3 (Just to frame the example a ...
Themistocles asked 18/8, 2011 at 3:29

3

Solved

I'd like to read at most 20 lines from a csv file: rows = [csvreader.next() for i in range(20)] Works fine if the file has 20 or more rows, fails with a StopIteration exception otherwise. Is th...
Pacha asked 9/7, 2009 at 23:9
1

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