splat Questions
4
Solved
Have you seen a function declared like this?
def foo a, **b
...
end
I understand that a single * is the splat operator. What does ** mean?
3
Solved
I am using the built in dependency injector/splat injector inside ReactiveUI.
I have constructors where I want to pass along their applicable data repository.
In other frameworks it just uses ref...
Agra asked 18/9, 2015 at 8:32
9
Solved
What is the correct name for operator *, as in function(*args)? unpack, unzip, something else?
7
Solved
Consider, for example,
squares = *map((2).__rpow__, range(5)),
squares
# (0, 1, 4, 9, 16)
*squares, = map((2).__rpow__, range(5))
squares
# [0, 1, 4, 9, 16]
So, all else being equal we get a li...
Lewandowski asked 21/5, 2019 at 11:54
1
I have a bunch of structs like this with increasing number of members, but consistent member naming:
struct one { int a; };
struct two { int a; int b; };
struct three { int a; int b; int c; };
I...
Blockhead asked 14/6, 2019 at 2:16
2
Solved
I have this code:
function test(...$strings)
{
// ...
}
It allows me to call test() like this:
test('a', 'series of', 'strings go here');
Which works. However, I often would like to do:
tes...
3
Solved
Ruby 2.3 introduces a new method on Array and Hash called dig. The examples I've seen in blog posts about the new release are contrived and convoluted:
# Hash#dig
user = {
user: {
address: {
st...
4
Solved
You can destructure an array by using the splat operator.
def foo(arg1, arg2, arg3)
#...Do Stuff...
end
array = ['arg2', 'arg3']
foo('arg1', *array)
But is there a way to destruct a hash for opti...
2
Solved
Someone asked about the splat operator yesterday, and I wanted to see the source code... would that be written in C or in Ruby? Where would it be found?
1
Solved
Case statement:
case x
when 1
"one"
when 2
"two"
when 3
"three"
else
"many"
end
is evaluated using the === operator. This operator is invoked on the value of the when expression with the val...
4
Solved
Setting a default value for a splat argument gives an error:
1.9.3-p374 :001 > def a b, *c = nil
1.9.3-p374 :002?> end
SyntaxError: (irb):1: syntax error, unexpected '=', expecting ';' or '\...
2
Solved
I noticed what I find to be a very surprising behavior with the ** (double-splat) operator in Ruby 2.1.1.
When key-value pairs are used before a **hash, the hash remains unmodified; however, when ...
Debug asked 25/4, 2014 at 0:49
2
My understanding is that a single splat on a non-array object calls to_a and then dissociates the elements apart. And since nil.to_a is defined to be [], the following conversion happens:
[:foo, *...
Ramtil asked 7/12, 2015 at 3:4
5
Solved
When looking at the source code for raphael or g.raphael or other libraries I've noticed the developer does something like this:
var val = Math.max.apply(Math, data_array);
Why not just invoke t...
Velda asked 9/5, 2011 at 12:3
0
I'm using Visual Studio 13 Community. Created a simple WinForms project, created an empty class and inherited ReactiveObject. I've installed reactivui-winforms 6.5.0 using NuGet. I can see ver 1.0....
Leavetaking asked 21/6, 2015 at 11:26
1
Solved
I have a method that should take 1+ parameters of any class, similar to Array#push:
def my_push(*objects)
raise ArgumentError, 'Needs 1+ arguments' if objects.empty?
objects.each do |obj| ...
Polygamous asked 23/5, 2015 at 18:28
1
Solved
I am trying to write a function that calls several functions that accept named parameters. I'd like the A function to be able to named parameters splatted together in args and pass along the matchi...
1
Solved
While reading about Julia on http://learnxinyminutes.com/docs/julia/ I came across this:
# You can define functions that take a variable number of
# positional arguments
function varargs(args...)...
2
Solved
Why do Ruby (2.0) procs/blocks with splat arguments behave differently than methods and lambdas?
def foo (ids, *args)
p ids
end
foo([1,2,3]) # => [1, 2, 3]
bar = lambda do |ids, *args|
p ids...
1
Solved
All values for b below let me call a method with the *args syntax.
def some_method(a)
puts a
end
b = 1
some_method(*b) # => 1
b = false
some_method(*b) # => false
b = "whatever"
some_met...
1
I discovered this after playing around with object ids.
ObjectSpace._id2ref(2648)
=> :**
ObjectSpace._id2ref(6688)
=> :**
ObjectSpace._id2ref(2648) == ObjectSpace._id2ref(6688)
=> false
...
2
Solved
How do you override the result of unpacking syntax *obj and **obj?
For example, can you somehow create an object thing which behaves like this:
>>> [*thing]
['a', 'b', 'c']
>>> ...
Arterial asked 12/3, 2014 at 23:15
2
Solved
In Ruby I can call methods with array elements used as positional parameters like this
method(fixed_arg1, fixed_arg2, *array_of_additional_args)
Here the "*" operator expands the array in place....
Permission asked 9/6, 2012 at 10:52
4
Solved
I know splat arguments are used when we do not know the number of arguments that would be passed. I wanted to know whether I should use splat all the time. Are there any risks in using the splat ar...
3
Solved
I've found it's available in Ruby, but I recognize it from what I've done in Python; the "splat" operator. Long story short, I'm wondering if there's a simpler way to accomplish what I currently am...
Choline asked 27/7, 2013 at 0:28
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