safe-bool-idiom Questions
3
Solved
I have another question related to the safe bool idiom:
typedef void (Testable::*bool_type)() const; // const necessary?
void this_type_does_not_support_comparisons() const {} // const necessary?
...
Jampan asked 11/8, 2011 at 15:0
2
Solved
Does the boost library provide an implementation of a safe bool idiom, so that I could derive my class from it?
If yes - where is it?
If no - what are my alternatives beyond implementing it mysel...
Negotiant asked 2/8, 2012 at 16:11
4
Solved
I'm trying to design a bool wrapper struct applying the safe bool idiom.
The classic implementation to solve this is pretty trivial: the skeleton could be something like this:
struct Bool final
{
...
Zosema asked 16/1, 2017 at 20:40
8
Solved
Consider the following excerpt from the safe bool idiom:
typedef void (Testable::*bool_type)() const;
operator bool_type() const;
Is it possible to declare the conversion function without the ty...
Monosaccharide asked 9/8, 2011 at 15:30
1
Solved
I'm trying to leverage boost::bool_testable<> (from Boost.Operators) to implement the safe bool idiom for a class, but the most recent version of the library (1.49 as of this post) doesn't se...
Centrum asked 7/5, 2012 at 23:50
2
I'm thinking of replacing all the instances of safe bool idiom by explicit operator bool in code which already uses C++11 features (so the fact that older compilers don't recognized explicit conver...
Telson asked 21/2, 2012 at 18:45
2
Solved
This answer of @R. Martinho Fernandes shows, that the safe-bool idiom is apperently deprecated in C++11, as it can be replaced by a simple
explicit operator bool() const;
according to the standa...
Maribeth asked 5/6, 2011 at 12:1
2
Solved
25% of programmers work time is spended by checking if the required code already exist.
I'm searching for a base class for implementing the safe bool idiom.
Befuddle asked 30/7, 2011 at 14:52
3
Solved
Could someone explain me why this code:
class safe_bool_base
{ //13
protected:
typedef void (safe_bool_base::*bool_type)() const;
void this_type_does_not_support_comparisons() const {} //18
...
Hawser asked 7/9, 2010 at 9:41
1
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