regfreecom Questions

4

Solved

I know that we can use CoLoadLibrary and DllGetClassObject to get the IClassFactory interface and get the COM component interface without registering the DLL. But what about a COM component in an ...
Greerson asked 9/7, 2010 at 9:22

3

Solved

I started with a very sophisticated system of clients and servers with COM references and other things, and I've cut down and down until I realized I can't even get Microsoft sample code to work fo...
Coagulant asked 25/11, 2015 at 21:31

2

Solved

Windows allows use of a COM object without having to register the COM dll. The mechanism is to include a "dependent assembly" in the application's manifest: MyProgram.exe.manifest <?xml ver...
Laboured asked 6/2, 2012 at 15:48

5

We are working on an integration of a large MFC-based application with a handful of managed (.NET) add-ins. Communication with these add-ins is done via COM. Historically, we've just used the regi...
Comfit asked 29/10, 2009 at 16:3

6

Solved

Is it possible to use an ocx (ActiveX Control) on a winform (probably adding it programatically) without first having the ocx registered with regsrv32? What I'm trying to achieve is to enable xcop...
Gadoid asked 24/10, 2008 at 18:20

5

Solved

I have some applications (some native, some .NET) which use manifest files so that they can be deployed in complete isolation, without requiring any global COM registration. For example, the depend...
Flatt asked 21/1, 2009 at 16:7

1

Solved

My Delphi application Client.exe needs a couple of .tlb files to work. These files define server interfaces. The corresponding object instances are created with System.Win.ComObj.CreateRemoteComObj...
Corroborant asked 22/3, 2016 at 12:25

1

Solved

I am currently working on a mixed managed / native work chain and need to create an activation context for registration-free COM support (see Embed a Registration-Free COM manifest into a C# dll wi...
Sedate asked 22/10, 2014 at 18:53

1

Solved

I'm currently working on a mixed native / managed application chain, which employs registration-free COM. The following image illustrates this: The C# wrapper DLL has been created using the tlbi...
Langbehn asked 24/9, 2014 at 19:6

1

I'm trying to use COM functions exposed by an EXE. I've created a C# project using Visual Studio 2010 (on a windows7/x64 machine) and added the reference to that EXE, then set the Isolated flag to ...
Myrt asked 18/1, 2012 at 17:0

1

Solved

Does anyone know which relation may exist between registration-free COM and drag/drop functionality? Specifically, we have a huge C++ CAD/CAM application comprising a number of EXEs and several hu...
Binucleate asked 1/4, 2014 at 16:14

1

Solved

I have a COM visible .NET class which exposes events and is used from VB6. For the last couple of days I have been trying to get this to work with regfree COM, but without success. The VB6 event ...
Duumvirate asked 28/4, 2014 at 12:29

2

In one of my Project, I have c# application which is using C++ DLL. Currently at client PC we are registering C++ DLLS at COM components in the registry so that we will use them in C#. I learn on ...
Urena asked 9/2, 2012 at 11:17

1

Solved

TL;DR Do all registry entries produced by regsvr32 need to be present in a SxS reg-free-COM manifest and vice versa? I'm trying to get registration free COM going for a third party component. R...
Vaporescence asked 10/10, 2013 at 13:36

1

Solved

The problem I'm facing is essentially described here, that is: I have a DLL that is using a 3rd party in-process COM component dll. I want to use registration free COM with that in-process compone...
Akkerman asked 10/10, 2013 at 15:1

1

UPDATE: After spending 20+ hours trying to get a simple example working, I have realized that this is not as simple as it seems. Articles like this reveal the "gotchas" - and this was written befor...
Mcgee asked 19/3, 2013 at 15:6

2

I'm curently trying to get registration-free COM working with Excel as the client, and a .NET dll as the server. Currently I'm simply trying to get a proof-of-concept working but am having trouble....
Freshwater asked 21/3, 2012 at 13:5

1

I have an ActiveX control (created using C#) that I am adding to a form in Visual FoxPro using late binding. It works without problems when I register the control. I want to use reg free COM and ...
Severe asked 20/5, 2010 at 19:34

3

Is there a way to activate a COM component which is an EXE COM application and also it's dependent COM dlls? I want to activate this COM component from .NET application(VS 2005/VS 2008). The path...
Wampler asked 22/6, 2009 at 9:11

2

Solved

We use manifest files to do registration-free COM, as I've also elaborated on in this other question. Now we're trying to use registration-free COM with an application that supports plug-ins. The ...
Teliospore asked 20/11, 2009 at 13:36

3

Solved

Until recently, we were happily using registration-free COM for our native and .NET COM components. However, we ran into a weird issue where our application started crashing randomly on windows XP ...
Putnem asked 6/3, 2009 at 0:10

1

Solved

I am trying to access a VB.NET DLL (.NET FX 4.0) from a VB6 client in a reg-free scenario. I tried to follow the example from http://msdn.microsoft.com/en-us/library/ms973915.aspx, but with no suc...
Defend asked 13/7, 2012 at 11:26

2

Solved

I want to add a registration-free COM reference to my .NET app. Registration-free means users can run the app without registering the COM component to their system. I found a number of articles on...
Watkins asked 1/6, 2012 at 22:59

8

Solved

I have some .NET code I use from VB6 code. I have always developed this on an XP machine by creating a VB6.exe.manifest file that listed the dependent .NET assemblies. For example, say my 2 .NET ...
Accuracy asked 30/12, 2010 at 17:59

2

Solved

I've built a COM client application that uses two COM server dlls; I want this application to run without COM registration - ie: winsxs / .manifests I get a (...almost expected...) "Class not regi...
Quart asked 16/2, 2011 at 16:17

© 2022 - 2024 — McMap. All rights reserved.