posixlt Questions
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Disclaimer: The title of the question might be wrong, because I don't know what causes this behaviour. The 'issue' is that viewing a POSIXlt object in RStudio viewer shows an infinite linked list, ...
1
I recently came across R code that compared a POSIXlt date object with a date string.
as.POSIXlt.date("2007-02-02") >= "2007-02-01"
[1] FALSE
The result, surprisingly at least for me, was FAL...
2
Solved
I have 2 data sets, each containing a date-time value in POSIXlt format, and some other numeric and character variables.
I want to combine both data sets based on the date-time column.
But the dat...
3
I have a column in my dataframe as datetime (factor) with the values as "15-10-2017 16:41:00".
I wanted this data to be converted as "2017-10-15 16:41:00".
When i try to convert...
2
Solved
I am interested, what "ct" and "lt" (in POSIXct and POSIXlt) mean. Are they some kind of abbreviations? E.g., does "ct" mean "calendar time" and "lt" something else?
1
Solved
I recently came across dplyr and - as a newbie - like it very much. Hence, I try to convert some of my base-R code into dplyr-code.
Working with air traffic control data, I am struggling with coe...
3
Solved
I have a problem. I downloaded data and tranformed dates into POSIXlt format
df<-read.csv("007.csv", header=T, sep=";")
df$transaction_date<-strptime(df$transaction_date, "%d.%m.%Y")
df$inst...
3
1) R version 3.4.4 (2018-03-15)
my.timedate <- as.POSIXlt('2016-01-01 16:00:00')
# print(attributes(my.timedate))
print(my.timedate[['hour']])
[1] 16
2) R version 3.5.0 (2018-04-23)
my....
1
This snippet
options(digits.secs=3)
s<-"12:00:00.188"
fmt<-"%I:%M:%OS"
print(strptime(s,fmt))
print(as.POSIXct(strptime(s,fmt)))
gives this textual output:
[1] "2017-09-12 00:00:00.188 CE...
1
I am not sure why it seems so difficult to find information regarding summarizing non-quantitative variables with stargazer.
I would like a summary of the following time variable (number of observ...
1
Solved
My question comes from this question. The question had the following character string.
x <- "2007-02-01 00:00:00"
y <- "02/01/2007 00:06:10"
If you try to convert this string to date-class...
2
Solved
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