In On Lisp, p. 267, Paul Graham provides an implementation of continuation passing macros: (setq *cont* #'identity) (defmacro =lambda (parms &body body) `#'(lambda (*cont* ,@parms) ,@body)) ...

This passage from On Lisp is genuinely confusing -- it is not clear how returning a quoted list such as '(oh my) can actually alter how the function behaves in the future: won't the returned list b...

I'm working my way through Graham's book "On Lisp" and can't understand the following example at page 37: If we define exclaim so that its return value incorporates a quoted list, (defun exclaim ...