Is there any way to efficiently do this, perhaps through toBuffer or to methods? My real problem is I'm building a List off a parser, as follows: lazy val nodes: Parser[List[Node]] = phrase(( node...

I have a ListBuffer. I want to remove all elements that meet a certain condition. I could iterate over it and remove each element. But what doe Scala say about mutating a list that you are iterati...

What is the most efficient way to create empty ListBuffer ? val l1 = new mutable.ListBuffer[String] val l2 = mutable.ListBuffer[String] () val l3 = mutable.ListBuffer.empty[String] There are an...