lifting Questions
1
Solved
I'm new to Haskell and learning about Monad Transformer. I found that lift can be omitted when operating on an inner monad in a monad stack. For example:
type Foo = ReaderT String (WriterT String I...
3
Solved
Let's say I have this (arguably mislead) piece of code laying around:
import System.Environment (getArgs)
import Control.Monad.Except
parseArgs :: ExceptT String IO User
parseArgs =
do
args <...
Conn asked 4/1, 2016 at 9:55
2
Solved
I have a bunch of arity aware lift functions:
const chain = f => xs =>
xs.reduce((acc, x) => acc.concat(f(x)), []);
const of = x => [x];
const add = (x, y) => x + y;
...
Schipperke asked 5/3, 2019 at 20:16
4
Solved
Sometimes when I read articles in the Scala ecosystem I read the term "lifting" / "lifted". Unfortunately, it is not explained what that exactly means. I did some research, and it seems that liftin...
Longstanding asked 31/7, 2013 at 8:16
2
Solved
I am learning monad transformers and I am confused about when using lift is necessary.
Assume that I have the following code (It's not doing anything interesting, just the simplest I could come wit...
Debtor asked 21/7, 2017 at 11:13
3
Solved
Looking at the source for Ramda.js, specifically at the "lift" function.
lift
liftN
Here's the given example:
var madd3 = R.lift(R.curry((a, b, c) => a + b + c));
madd3([1,2,3], [1,2,3], [1...
Pickar asked 11/4, 2016 at 20:26
1
Solved
I usually hear the term lifting, when people are talking about map, fold, or bind, but isn't basically every higher order function some kind of lifting?
Why can't filter be a lift from a -> Boo...
Turtleback asked 18/4, 2017 at 21:48
2
Solved
Given the following:
var average = R.lift(R.divide)(R.sum, R.length)
How come this works as a pointfree implementation of average? I don't understand why I can pass R.sum and R.length when they...
Alisander asked 17/9, 2016 at 10:47
1
Solved
I am trying to take e.g. ExceptT a (StateT A M), for some concrete type A and monad M, and wrap them up into my new custom monads.
First I identified that StateT A M appears often in other context...
Ferminafermion asked 14/9, 2015 at 19:9
1
Solved
In Haskell, is there any alias for (liftM . liftM), (liftM . liftM . liftM) etc?
So that I don't have to be so verbose, e.g.:
(liftM . liftM) (+ 1) [Just 1, Just 2] = [Just 2, Just 3]
(liftM2 . l...
3
Solved
I was reviewing some code and came across the following gem, which I'd wager is a copy-paste of pointfree output:
(I thought the following would more appropriate than the usual foo/bar for this p...
1
I want to lift a Haskell function into in a higher-order lambda calculus encoding. This is taken almost verbatim from Oleg's Typed Tagless Final encoding.
class Lam r where
emb :: a -> r a
(^...
1
Solved
In the book Functional Programming In Scala, there's an example of 'Lift' where a function with type A => B is promoted to Option[A] => Option[B].
This is how lift is implemented:
def lift[...
Jobie asked 22/6, 2013 at 23:26
4
Solved
I wrote a Scala function:
def liftOrIdentity[T](f: (T, T) => T) = (a: Option[T], b: Option[T]) =>
(a, b) match {
case (Some(a), None) => Some(a)
case (None, Some(b)) => Some(b)
ca...
Faso asked 19/6, 2013 at 9:49
1
Solved
I'm having a bit of difficulty with monad transformers at the moment. I'm defining a few different non-deterministic relations which make use of transformers. Unfortunately, I'm having trouble unde...
1
Solved
The Short Version (TL;DR):
Suppose I have an expression that's just a chain of member access operators:
Expression<Func<Tx, Tbaz>> e = x => x.foo.bar.baz;
You can think of this e...
Cydnus asked 19/6, 2012 at 19:45
4
I'm testing performance differences using various lambda expression syntaxes. If I have a simple method:
public IEnumerable<Item> GetItems(int point)
{
return this.items.Where(i => i.IsAp...
Jean asked 29/11, 2011 at 2:37
1
Solved
I'm trying to construct a function of type:
liftSumthing :: ((a -> m b) -> m b) -> (a -> t m b) -> t m b
where t is a monad transformer. Specifically, I'm interested in doing this...
Microbe asked 11/2, 2012 at 19:11
1
Solved
In Haskell, liftM2 can be defined as:
liftM2 :: (Monad m) => (a1 -> a2 -> r) -> m a1 -> m a2 -> m r
liftM2 f m1 m2 = do
x1 <- m1
x2 <- m2
return $ f x1 x2
I'd like to ...
1
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