jquery-after Questions
6
Solved
Please have a look at: http://jsfiddle.net/s6VdW/
HTML:
<div id="test"></div>
JS:
var span1 = $("<span/>").text("Hello");
var br = $("<br/>");
var span2 = $("<span/&...
Reeta asked 13/3, 2013 at 10:1
4
Solved
Insofar as I can tell, the following code should work, creating a <div> element, and then creating a <p> element; the expression should result in a jQuery object with two elements:
$("...
Hypostatize asked 7/5, 2012 at 21:21
3
Simple really but cannot get it to work, here is my script...
$('body').after('<div id="lightBox" style="height: ' + htmlHeight + 'px;"></div>');
How can I get it to fade in rather t...
Noella asked 8/10, 2011 at 23:28
11
Solved
jQuery has an .after() method, and also an .insertAfter() method.
What's the difference between them? I think I can use .after() to insert elements after a selected element (or elements). Is that...
Warrenwarrener asked 15/12, 2009 at 15:34
9
Solved
I am pretty proficient with coding, but now and then I come across code that seems to do basically the same thing. My main question here is, why would you use .append() rather then .after() or vice...
Bielefeld asked 13/2, 2013 at 4:42
3
Solved
I have a <ul> with a number of <li> elements in it. A number of them are hidden and are added to the end of the list upon clicking with jQuery after().
However, for some reason, the el...
Expressway asked 9/4, 2014 at 10:55
2
Solved
Possible Duplicate:
Why does jQuery .after() not chain the new element?
This reference code:
$("#id").after(string);
Does a pretty good job inserting the element of the string wher...
Siddra asked 27/7, 2012 at 21:32
3
Solved
I am curious why jQuery's .after() does not chain, or "provide you with," the new element that you create with it. It seems to me like it should, but I am no expert and was hoping someone could she...
Lisandralisbeth asked 20/6, 2012 at 6:50
2
Solved
I'm trying to split an unordered list into two columns by finding the halfway point of the list and adding </ul><ul> after that </li>. This could be the complete wrong way to do t...
Botulin asked 2/1, 2012 at 23:40
1
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