I'm using custom exceptions to differ my exceptions from Python's default exceptions.
Is there a way to define a custom exit code when I raise the exception?
class MyException(Exception):
pass
def do_something_bad():
raise MyException('This is a custom exception')
if __name__ == '__main__':
try:
do_something_bad()
except:
print('Oops') # Do some exception handling
raise
In this code, the main function runs a few functions in a try code. After I catch an exception I want to re-raise it to preserve the traceback stack.
The problem is that 'raise' always exits 1. I want to exit the script with a custom exit code (for my custom exception), and exit 1 in any other case.
I've looked at this solution but it's not what I'm looking for: Setting exit code in Python when an exception is raised
This solution forces me to check in every script I use whether the exception is a default or a custom one.
I want my custom exception to be able to tell the raise function what exit code to use.
try
/except
clause. – Haphtarah