Bi-Cubic Interpolation Algorithm for Image Scaling
Asked Answered
E

4

11

I'm trying to write a basic bicubic resize algorithm to resize a 24-bit RGB bitmap. I have a general understanding of the math involved, and I'm using this implementation from Google Code as a guide. I'm not using any external libraries here - I'm just experimenting with the algorithm itself. The bitmap is represented as a plain std::vector<unsigned char>:

inline unsigned char getpixel(const std::vector<unsigned char>& in, 
    std::size_t src_width, std::size_t src_height, unsigned x, unsigned y, int channel)
{
    if (x < src_width && y < src_height)
        return in[(x * 3 * src_width) + (3 * y) + channel];

    return 0;
}

std::vector<unsigned char> bicubicresize(const std::vector<unsigned char>& in, 
    std::size_t src_width, std::size_t src_height, std::size_t dest_width, std::size_t dest_height)
{
    std::vector<unsigned char> out(dest_width * dest_height * 3);

    const float tx = float(src_width) / dest_width;
    const float ty = float(src_height) / dest_height;
    const int channels = 3;
    const std::size_t row_stride = dest_width * channels;

    unsigned char C[5] = { 0 };

    for (int i = 0; i < dest_height; ++i)
    {
        for (int j = 0; j < dest_width; ++j)
        {
            const int x = int(tx * j);
            const int y = int(ty * i);
            const float dx = tx * j - x;
            const float dy = ty * i - y;

            for (int k = 0; k < 3; ++k)
            {
                for (int jj = 0; jj < 4; ++jj)
                {
                    const int z = y - 1 + jj;
                    unsigned char a0 = getpixel(in, src_width, src_height, z, x, k);
                    unsigned char d0 = getpixel(in, src_width, src_height, z, x - 1, k) - a0;
                    unsigned char d2 = getpixel(in, src_width, src_height, z, x + 1, k) - a0;
                    unsigned char d3 = getpixel(in, src_width, src_height, z, x + 2, k) - a0;
                    unsigned char a1 = -1.0 / 3 * d0 + d2 - 1.0 / 6 * d3;
                    unsigned char a2 = 1.0 / 2 * d0 + 1.0 / 2 * d2;
                    unsigned char a3 = -1.0 / 6 * d0 - 1.0 / 2 * d2 + 1.0 / 6 * d3;
                    C[jj] = a0 + a1 * dx + a2 * dx * dx + a3 * dx * dx * dx;

                    d0 = C[0] - C[1];
                    d2 = C[2] - C[1];
                    d3 = C[3] - C[1];
                    a0 = C[1];
                    a1 = -1.0 / 3 * d0 + d2 -1.0 / 6 * d3;
                    a2 = 1.0 / 2 * d0 + 1.0 / 2 * d2;
                    a3 = -1.0 / 6 * d0 - 1.0 / 2 * d2 + 1.0 / 6 * d3;
                    out[i * row_stride + j * channels + k] = a0 + a1 * dy + a2 * dy * dy + a3 * dy * dy * dy;
                }
            }
        }
    }

    return out;
}

Problem: When I use this algorithm to downscale an image, it works except the output image contains all black pixels on the right side for some reason, giving the appearance that it's been "cropped".

Example:

INPUT IMAGE:

enter image description here

OUTPUT IMAGE:

enter image description here

Question: Reviewing the algorithm, I can't see why this would happen. Does anyone see the flaw here?

Electrum answered 2/3, 2013 at 16:52 Comment(1)
Well, based on that output image, it looks exactly like you've only calculated a square's worth of output pixels. That should be a big enough clue for you to debug and diagnose this yourself...Imeldaimelida
D
13

try not exchanging width and height.

   for (int i = 0; i < dest_width; ++i)
    {
        for (int j = 0; j < dest_height; ++j)
Decorticate answered 2/3, 2013 at 17:1 Comment(2)
Traversing in his way is cache friendly, it will execute faster. As opposed to your suggestion that cause cache misses for big images.Carriole
the problem was in the bounds of indexes. And the cache misses are cache-size and compiler setting dependent...Decorticate
G
2

I suggest don't use this function because it was written very bad. You need to make two convolutions: at first by X coordinate then by Y. In this function all these convolutions are making in the same time that leads to very slow work. And if You would look at jj loop body you could notice that all second part of body begining from "d0 = C[0] - C[1];" could be moved outside jj loop because only the last iteration of this loop takes effect on out[] array (all previous iterations results will be overwrited).

Gemmagemmate answered 27/12, 2014 at 6:17 Comment(1)
I agree. It also seems to me that this implementation doesn't work correctly when reducing the size of the image. The inner loop needs to consider ALL the source pixels that cover the area of the destination pixel. This implementation only considers a 4x4 grid of pixels. The best explanation of image resampling I have found is: entropymine.com/imageworsener/resample An on the specifics of bicubic resampling: entropymine.com/imageworsener/bicubicMarcosmarcotte
H
1

You should switch the x and z when you call getpixel, and in getpixel you should index the array using:

[(y * 3 * src_width) + (3 * x) + channel]
Hollyhock answered 4/11, 2014 at 13:25 Comment(0)
A
1

In getpixel(in, src_width, src_height, z, x, k):

z mean horizontal offset
x mean vertical offset

So just need patch the getpixel function, below is the patched code:

inline unsigned char getpixel(const std::vector<unsigned char>& in, 
    std::size_t src_width, std::size_t src_height, unsigned y, unsigned x, int channel)
{
    if (x < src_width && y < src_height)
        return in[(y * 3 * src_width) + (3 * x) + channel];

    return 0;
}

std::vector<unsigned char> bicubicresize(const std::vector<unsigned char>& in, 
    std::size_t src_width, std::size_t src_height, std::size_t dest_width, std::size_t dest_height)
{
    std::vector<unsigned char> out(dest_width * dest_height * 3);

    const float tx = float(src_width) / dest_width;
    const float ty = float(src_height) / dest_height;
    const int channels = 3;
    const std::size_t row_stride = dest_width * channels;

    unsigned char C[5] = { 0 };

    for (int i = 0; i < dest_height; ++i)
    {
        for (int j = 0; j < dest_width; ++j)
        {
            const int x = int(tx * j);
            const int y = int(ty * i);
            const float dx = tx * j - x;
            const float dy = ty * i - y;

            for (int k = 0; k < 3; ++k)
            {
                for (int jj = 0; jj < 4; ++jj)
                {
                    const int z = y - 1 + jj;
                    unsigned char a0 = getpixel(in, src_width, src_height, z, x, k);
                    unsigned char d0 = getpixel(in, src_width, src_height, z, x - 1, k) - a0;
                    unsigned char d2 = getpixel(in, src_width, src_height, z, x + 1, k) - a0;
                    unsigned char d3 = getpixel(in, src_width, src_height, z, x + 2, k) - a0;
                    unsigned char a1 = -1.0 / 3 * d0 + d2 - 1.0 / 6 * d3;
                    unsigned char a2 = 1.0 / 2 * d0 + 1.0 / 2 * d2;
                    unsigned char a3 = -1.0 / 6 * d0 - 1.0 / 2 * d2 + 1.0 / 6 * d3;
                    C[jj] = a0 + a1 * dx + a2 * dx * dx + a3 * dx * dx * dx;

                    d0 = C[0] - C[1];
                    d2 = C[2] - C[1];
                    d3 = C[3] - C[1];
                    a0 = C[1];
                    a1 = -1.0 / 3 * d0 + d2 -1.0 / 6 * d3;
                    a2 = 1.0 / 2 * d0 + 1.0 / 2 * d2;
                    a3 = -1.0 / 6 * d0 - 1.0 / 2 * d2 + 1.0 / 6 * d3;
                    out[i * row_stride + j * channels + k] = a0 + a1 * dy + a2 * dy * dy + a3 * dy * dy * dy;
                }
            }
        }
    }

    return out;
}
Almoner answered 9/7, 2015 at 4:29 Comment(0)

© 2022 - 2024 — McMap. All rights reserved.