java & operator with two integers?

Question

From what I understand the & operator is similar to the && operator except that the && only checks the second if the first is true, while the & checks both regardless of the result of the first one. Basically the && just saves a little time and power.

If that is so, then how does this code work?

int l = 0;
if ((l & 8) != 0 && (l & 4) == 0){ do something}

what does the (l & 8) and the (l & 4) do? What does the & do in this case?

Pasteboard

This is a bitwise AND operator. docs.oracle.com/javase/tutorial/java/nutsandbolts/op3.html – Princess

By the way, this is equivalent to if ((l & 12) == 8) { do something } – Capita

Answer 1

& and && are two different operators but the difference is not what you've described.

& does the bit-wise AND of two integers and produces a third integer whose bit are set to 1 if both corresponding bits in the two source integers are both set to 1; 0 otherwise.

&& applies only to two booleans and returns a third boolean which will be true if both the input booleans are true; false otherwise.

Behave

That makes a lot more sense. Does it use the binary codes from ASCII, or just straight binary 0 being 0, 1 being 1, 10 being 2, and so on? – Pasteboard

To use your terminology it uses "just straight binary 0 being 0, 1 being 1, 10 being 2, and so on", which is known as binary number. ASCII is a way of coding "written alphabet" characters to a binary numbers (aka character-encoding). There exist others like EBCDIC or UNICDE – Behave