Cannot convert type 'Newtonsoft.Json.Linq.JObject' to Complex Type

Question

I have json as follows,

{
  "H": "Macellum",
  "M": "Receive",
  "A": [
    {
      "CustomerId": "172600",
      "OrderId": "69931",
      "OrderStatus": "E0",
      "Buy": "A"
    }
  ]
}

and complex type

public class OrderStats
{
    public string CustomerId { get; set; }
    public string OrderId { get; set; }
    public string OrderStatus { get; set; }
    public string Buy { get; set; }
}

I am trying a casting as follows,

dynamic obj = JsonConvert.DeserializeObject<dynamic>(message);
OrderStats info = (OrderStats)obj.A[0]; //exception
OrderStats info = obj.A[0] as OrderStats; //info is null

But error as follows

Cannot convert type 'Newtonsoft.Json.Linq.JObject' to OrderStatus

Fourthclass

Answer 1

How about this one?

var str = "YOUR_JSON_HERE";
var obj = JsonConvert.DeserializeObject<dynamic>(str);
OrderStats info = ((JArray)obj.A)[0].ToObject<OrderStats>();

Hazardous

Please pay attention that there is missing comma at the end of "M": "Receive" – Hazardous

I can not change the class structure – Fourthclass

Don't you have a compilation error: 'OrderStatus': member names cannot be the same as their enclosing type? – Hazardous

I am sorry for typo again, class name is OrderStats – Fourthclass

I have fixed answer – Hazardous

Let us continue this discussion in chat. – Hazardous

Solution if you don't have an array: ((JObject)Tags).ToObject<OrderStats>(); – Wastage

Answer 2

I found a solution a bit trivial like this,

dynamic obj = JsonConvert.DeserializeObject<dynamic>(message);
OrderStats info = JsonConvert.DeserializeObject<OrderStats>(JsonConvert.SerializeObject(obj.A[0]));

Fourthclass

Because your error come from Cannot convert type 'Newtonsoft.Json.Linq.JObject' to Complex Type but your post is Conver from JSON string to Complex Type. So that @viktor's solution is correct for string convert, and your solution here is correct for Linq.JObject convert. – Gauthier

Answer 3

i`m reviewing this solutions, but i think it's not necessary to use dynamic key,

i did this and it's work for me:

OrderStats info = JsonConvert.DeserializeObject(str)

It's simplified that other lines that you mention, but thanks for the advice, it was

correct for me

Bauhaus

Answer 4

string jsonString = "{\"name\": \"John Doe\", \"age\": 30, \"email\": \"[email protected]\"}";

// Parse the JSON string into a JObject
JObject jsonObject = JObject.Parse(jsonString);

// Convert the JObject into a complex type object
var person = jsonObject.ToObject<Person>();

Quartet