Why is Firefox 3 breaking with console.log
Asked Answered
H

6

11

I have the following:

console.log (a.time_ago() + ' ' + b.time_ago());

This is breaking in FireFox 3, meaning when FF hits that line in the JS, it goes no further. Strangely if I have Firebug open it doesn't break and continues as normal. Some how firebug prevents this issue?

I'm puzzled on this one. Any thoughts as to why console.log would break firefox 3, but not if firebug is open?

Thanks

Hooky answered 10/2, 2011 at 22:13 Comment(1)
Isn't console.log part of firebug? and hence if its not open, there's no container to paste to...Zippy
H
30

This is not just Firefox. Your code will stop working in every browser (except Chrome and safari (in some instances) because they have console.log() built in along with their developer tools.)

It is because when you don't have firebug open, the object "console" is not defined. You should take care never too leave console.log() functions in your code, or it will break in every browser.


I'd like to add that I have sometimes used this function:

function log () {
    if (typeof console == 'undefined') {
        return;
    }
    console.log.apply(console, arguments);
}

Then you can simply call:

log(somevar, anothervar);

and it will work the same way as console.log, but will not fail if firebug is not loaded (and is shorter to type :P)

Cheers

Hypermetropia answered 10/2, 2011 at 22:16 Comment(3)
You can use console.log(), just check if window.console exists before calling any console functions. E.g. if (window.console) console.log('Hello World');Brancusi
Thanks @generalhenry, I didn't know Safari also had it. That's helpful.Hypermetropia
Firefox 4 will also have the console object built in.Jampacked
M
4

In case, that firebug is closed, I overwrite the console object. So, you can implement fallback functions ...

console = console || { log : function() {
// place your logging code here, if firebug is closed
}, debug : function() {
// place your debug code here, if firebug is closed
} /*, [ and so on .. ] */ };

Greetings,

Dyvor

Major answered 10/2, 2011 at 22:35 Comment(0)
C
2

In FireFox if the console isn't open when you call to it a JavaScript error is thrown.

I wrap all my console.log's in a wrapper to check for console - you can either wrap the check around the console call or use a different name to alias console.

Aliasing

/* konsole is a safe wrapper for the Firebug console. */
var konsole = {
  log: function(args){},
  dir: function(args){},
  debug: function(args){},
  info: function(args){},
  warn: function(args){},
  error: function(args){}
};
// Remove below here when in production
if (typeof window.console != 'undefined' && typeof window.console.log == 'function') {
  konsole = window.console;
}
konsole.log('testing debugging');
konsole.error('throw an error message to the console');

Check for console

if (typeof window.console != 'undefined' && typeof window.console.log == 'function') {
  console.log('testing debugging');
  console.error('throw an error message to the console');
}
Chuipek answered 10/2, 2011 at 22:20 Comment(0)
P
1

I always do a if (console) check to make sure the console actually exists. If firebug isn't open it's like you're acting upon a null object, thus why it breaks.

Papilloma answered 10/2, 2011 at 22:16 Comment(4)
A null object would silently swallow the logging, which would work fine...Heteromerous
@delnan: I think what bobber means is that console has the value null (which is not true, it is undefined). But in both cases the code will break.Fernando
@Felix: I know what he propably meant, I was just being pedantic.Heteromerous
@delnan. Shallow and pedantic. ;)Papilloma
A
1

Firefox doesn't have a console object. Firebug adds one.

The simply fix is to have firebug open for development and remove console.log statements for deployment.

you can also make a custom log function like

function log (msg)
{
  if(console)
  {
    console.log(msg);
  }
}

that will log only if console exists

Andromeda answered 10/2, 2011 at 22:18 Comment(2)
the problem with this function is that it won't accept multiple arguments and parameters the same way console.log() does and also if(console) is not really a good check for if an object is defined or not in javascript.Hypermetropia
the code snipit wasn't intended to be functional, just to get the idea across. I'd post a real example but you beat me too it :pAndromeda
P
0

To keep Firefox 3.0 from complaining reliably use the following...

if ('console' in window) {}
Pundit answered 6/7, 2014 at 22:38 Comment(0)

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