xmlserializer validation
Asked Answered
S

2

11

I'm using XmlSerializer to deserialize Xml achives. But I found the class xsd.exe generated only offers capability to read the xml, but no validation. For example, if one node is missing in a document, the attribute field of the generated class will be null, rather than throws a validation exception as I expected. How can I achieve that? Thanks!

Subtonic answered 10/11, 2009 at 3:14 Comment(0)
A
34

The following code should validate against a schema while deserializing. Similar code can be used to validate against a schema while serializing.

private static Response DeserializeAndValidate(string tempFileName)
{
    XmlSchemaSet schemas = new XmlSchemaSet();
    schemas.Add(LoadSchema());

    Exception firstException = null;

    var settings = new XmlReaderSettings
                   {
                       Schemas = schemas,
                       ValidationType = ValidationType.Schema,
                       ValidationFlags =
                           XmlSchemaValidationFlags.ProcessIdentityConstraints |
                           XmlSchemaValidationFlags.ReportValidationWarnings
                   };
    settings.ValidationEventHandler +=
        delegate(object sender, ValidationEventArgs args)
        {
            if (args.Severity == XmlSeverityType.Warning)
            {
                Console.WriteLine(args.Message);
            }
            else
            {
                if (firstException == null)
                {
                    firstException = args.Exception;
                }

                Console.WriteLine(args.Exception.ToString());
            }
        };

    Response result;
    using (var input = new StreamReader(tempFileName))
    {
        using (XmlReader reader = XmlReader.Create(input, settings))
        {
            XmlSerializer ser = new XmlSerializer(typeof (Response));
            result = (Response) ser.Deserialize(reader);
        }
    }

    if (firstException != null)
    {
        throw firstException;
    }

    return result;
}
Arleen answered 10/11, 2009 at 15:3 Comment(2)
Thanks for sharing this solution. As this puts the validation in-line with the deserialize by validating via the XmlReader, it is a better approach.Elfland
Regarding the hint "similar code can be used to validate agains a schema while serializing", there is a question here: https://mcmap.net/q/1013330/-validate-xml-during-serialization/5333340Kramlich
E
6

The following code will manually load and validate your XML against a schema file programmatically, allowing you to deal with any resulting errors and/or warnings.

//Read in the schema document
using (XmlReader schemaReader = XmlReader.Create("schema.xsd"))
{
    XmlSchemaSet schemaSet = new XmlSchemaSet();

    //add the schema to the schema set
    schemaSet.Add(XmlSchema.Read(schemaReader, 
    new ValidationEventHandler(
        delegate(Object sender, ValidationEventArgs e)
        {
        }    
    )));

    //Load and validate against the programmatic schema set
    XmlDocument xmlDocument = new XmlDocument();
    xmlDocument.Schemas = schemaSet;
    xmlDocument.Load("something.xml");

    xmlDocument.Validate(new ValidationEventHandler(
        delegate(Object sender, ValidationEventArgs e)
        {
            //Report or respond to the error/warning
        }
    )); 
 }

Now obviously you desire to have the classes generated by xsd.exe to do this automatically and while loading (the above approach would require a second handling of the XML file), but a pre-load validate would allow you to programmatically detect a malformed input file.

Elfland answered 10/11, 2009 at 3:56 Comment(2)
@John Saunders - I am doubting that the class generation code is likely to change its operation any time soon, and the msdn site shows no relevant options for xsd.exe, so I think it is reasonable to suggest a workaround...Elfland
In the question text, the OP expresses that he wants an exception to be thrown for an invalid input xml. This approach does accomplish that. I am not claiming that this is the only way it can be done, or even that it is the best way. But I was responding with an approach (off the top of my head) that I had used in the past to generally validate XML documents.Elfland

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