How can I delegate an implementation to a mutable property in Kotlin?
Asked Answered
M

1

12

As to my understanding, the idea of delegating an implementation in Kotlin is to avoid code that looks like this:

class MyClass(val delegate : MyInterface) : MyInterface
{
    override fun myAbstractFun1() = delegate.myAbstractFun1()
    override fun myAbstractFun2() = delegate.myAbstractFun2()
    // ...
}

Instead, we can write the following code which should do the same:

class MyClass(val delegate : MyInterface) : MyInterface by delegate

Now, I'd like delegate to be a mutable variable, i.e. my code looks like this:

var delegate : MyInterface = MyImplementation()
object MyObject : MyInterface by delegate

So if I'd delegated every abstract method to delegate by myself like in the first example, changing the value of delegate does change the behaviour of the methods. However, the above code compiles to this Java code:

public final class MyObject implements MyInterface {
    public static final MyObject INSTANCE;
    // $FF: synthetic field
    private final MyInterface $$delegate_0 = MyObjectKt.access$getDelegate$p();

    @NotNull
    public String myAbstractFun1() {
        return this.$$delegate_0.myAbstractFun1();
    }

    @NotNull
    public String myAbstractFun2() {
        return this.$$delegate_0.myAbstractFun2();
    }
}

So obviously, instead of just using the delegate field, the Kotlin compiler decides to copy it when creating MyObject to a final field $$delegate_0, which is not modified when I change the value of delegate

Is there a better solution for doing this instead of delegating every method manually?

Mitten answered 1/1, 2018 at 23:29 Comment(7)
What is the use case for this?Wisner
@Wisner I'm trying to have a global object that holds the configuration of my library as well as providing methods to modify it. I know there are different ways to accomplish this, but this seems like a convenient way to have properties and methods in one place without creating a wrapper classMitten
It doesn't even work if passing a proper object! It seems the compiler really, really want to know statically what's going to happen. I think that makes sense, too; if you implemented the methods yourself, they wouldn't change at runtime (unless reflection), so in order to have similar guarantees, the compiler needs to fix the delegate.Violaviolable
@Violaviolable I don't see how that makes sense, as a manually implemented method can change bedaviour when the instance variables change. So why shouldn't that be the case for auto-generated methods as well?Mitten
@Mitten A manually implemented method depends only on statically known declarations, and the compiler can reason about those (e.g. a val won't change). If you swap out the delegate -- potentially with a whole different class! -- what is declared as a val (in the delegate interface) suddenly changed. (Note how you could never ever delegate vals!) Therefore, if you allowed to swap out delegate objects, the compiler can rely on (far?) fewer things. Now, that doesn't imply one couldn't allow that; it's probably a trade-off.Violaviolable
I think a discussion about design choices would be better off on discuss.kotlinlang.org.Violaviolable
See (and vote for it) youtrack.jetbrains.com/issue/KT-83Roubaix
B
1

Sadly, as far as I know there is no way of changing the delegate by changing the original property content, but you might still be able to do something similar by working in an immutable way and copying the object:

interface MyInterface {
  fun foo():Int
}

data class MyClass(val delegate : MyInterface) : MyInterface by delegate

object ImplementationA: MyInterface { override fun foo() = 7 }
object ImplementationB: MyInterface { override fun foo() = 5 }

val objA = MyClass(ImplementationA)
println(objA.foo()) // returns 7

val objB = objA.copy(ImplementationB)
println(objB.foo()) // returns 5
println(objA.foo()) // still 7

Hope this is still useful.

Baroness answered 2/5, 2018 at 22:8 Comment(0)

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