Finding weekend days based on culture
Asked Answered
M

5

12

Is there a way to find the days that constitute a weekend or workweek based on different cultures using the .NET framework? For example, some Muslim countries have a workweek from Sunday through Thursday.

Metrify answered 7/1, 2010 at 8:35 Comment(2)
I think that .net framework does not support this feature. You have to implement with your own model.Purpose
A similar was question was asked if .NET already supports this. The answer is that it does not; you'll have to roll your own.Sesquicarbonate
S
5

No one had a solution for this so I wrote one. This uses the country to determine if a day is a workday, weekend, or 1/2 workday (Saturday in some countries). There is some ambiguity in this as in Mexico a 1/2 day on Saturday is "customary" but not official. For cases like this, I set it as work time.

This covers everything except 3 provinces in Malaysia, which are different from the rest of Malaysia. AFAIK, CultureInfo.Name does not have a distinct value for those 3 provinces. Most interesting country, Brunei where the weekend is Friday & Sunday, with Saturday a workday.

Code is downloadable as a project at Is it the weekend? Main code below:

using System;
using System.Globalization;

namespace windward
{
    /// <summary>
    /// Extensions for the CultureInfo class.
    /// </summary>
    public static class CultureInfoExtensions
    {
        /// <summary>
        /// The weekday/weekend state for a given day.
        /// </summary>
        public enum WeekdayState
        {
            /// <summary>
            /// A work day.
            /// </summary>
            Workday,
            /// <summary>
            /// A weekend.
            /// </summary>
            Weekend,
            /// <summary>
            /// Morning is a workday, afternoon is the start of the weekend.
            /// </summary>
            WorkdayMorning
        }

        /// <summary>
        /// Returns the English version of the country name. Extracted from the CultureInfo.EnglishName.
        /// </summary>
        /// <param name="ci">The CultureInfo this object.</param>
        /// <returns>The English version of the country name.</returns>
        public static string GetCountryEnglishName(this CultureInfo ci)
        {
            string[] parts = ci.EnglishName.Split(new[] {'(', ')'}, StringSplitOptions.RemoveEmptyEntries);
            if (parts.Length < 2)
                return ci.EnglishName;
            parts = parts[1].Split(new[] {','}, StringSplitOptions.RemoveEmptyEntries);
            return parts[parts.Length - 1].Trim();
        }

        /// <summary>
        /// Returns the English version of the language name. Extracted from the CultureInfo.EnglishName.
        /// </summary>
        /// <param name="ci">The CultureInfo this object.</param>
        /// <returns>The English version of the language name.</returns>
        public static string GetLanguageEnglishName(this CultureInfo ci)
        {
            string[] parts = ci.EnglishName.Split(new[] {'('}, StringSplitOptions.RemoveEmptyEntries);
            return parts[0].Trim();
        }

        /// <summary>
        /// Return if the passed in day of the week is a weekend.
        /// 
        /// note: state pulled from http://en.wikipedia.org/wiki/Workweek_and_weekend
        /// </summary>
        /// <param name="ci">The CultureInfo this object.</param>
        /// <param name="day">The Day of the week to return the stat of.</param>
        /// <returns>The weekday/weekend state of the passed in day of the week.</returns>
        public static WeekdayState IsWeekend(this CultureInfo ci, DayOfWeek day)
        {
            string[] items = ci.Name.Split(new[] {'-'}, StringSplitOptions.RemoveEmptyEntries);
            switch (items[items.Length - 1])
            {
                case "DZ": // Algeria
                case "BH": // Bahrain
                case "BD": // Bangladesh
                case "EG": // Egypt
                case "IQ": // Iraq
                case "IL": // Israel
                case "JO": // Jordan
                case "KW": // Kuwait
                case "LY": // Libya
                // Northern Malaysia (only in the states of Kelantan, Terengganu, and Kedah)
                case "MV": // Maldives
                case "MR": // Mauritania
                case "NP": // Nepal
                case "OM": // Oman
                case "QA": // Qatar
                case "SA": // Saudi Arabia
                case "SD": // Sudan
                case "SY": // Syria
                case "AE": // U.A.E.
                case "YE": // Yemen
                    return day == DayOfWeek.Thursday || day == DayOfWeek.Friday
                        ? WeekdayState.Weekend
                        : WeekdayState.Workday;

                case "AF": // Afghanistan
                case "IR": // Iran
                    if (day == DayOfWeek.Thursday)
                        return WeekdayState.WorkdayMorning;
                    return day == DayOfWeek.Friday ? WeekdayState.Weekend : WeekdayState.Workday;

                case "BN": // Brunei Darussalam
                    return day == DayOfWeek.Friday || day == DayOfWeek.Sunday
                        ? WeekdayState.Weekend
                        : WeekdayState.Workday;

                case "MX": // Mexico
                case "TH": // Thailand
                    if (day == DayOfWeek.Saturday)
                        return WeekdayState.WorkdayMorning;
                    return day == DayOfWeek.Saturday || day == DayOfWeek.Sunday
                        ? WeekdayState.Weekend
                        : WeekdayState.Workday;

            }

            // most common Saturday/Sunday
            return day == DayOfWeek.Saturday || day == DayOfWeek.Sunday ? WeekdayState.Weekend : WeekdayState.Workday;
        }
    }
}
Supernumerary answered 20/10, 2013 at 15:0 Comment(1)
so this is better? default: throw new NotImplementedException(); ,or // most common Saturday/Sunday return day == DayOfWeek.Saturday || day == DayOfWeek.Sunday ? WeekdayState.Weekend : WeekdayState.Workday; because it's common? i mean how common it isStratocumulus
I
4

The only thing i know is how to get the day the week starts. Perhaps this can help:

CultureInfo.CurrentCulture.DateTimeFormat.FirstDayOfWeek

from System.Globalization, perhaps you find in this package something.

There are several Calendar-Classses like JulianCalendar, HebrewCalendar and so on. It could be possible to find there what you want.

Indefeasible answered 7/1, 2010 at 12:51 Comment(1)
this wont help, as it doesn't says if this culture have two day as weekend or one dayStratocumulus
E
0

I won't give you a .NET answer, but I will say that you won't base it on "culture", but rather on country.

You can get country from IP with a fir degree of accuracy (but it will never be 100%). After that, I would suggest a lot of googling, because I doubt that you are going to find the code already written.

(you might also look into some open source calendar/appointment programs, especially widely-used ones, like on Linux, or maybe Lightning, the Thunderbird plug-in. If you wade through their code, you might find the data for this)

Fortunately, though, you just face a grind, rather than something difficult to implement.

Good luck!

Einsteinium answered 7/1, 2010 at 12:44 Comment(0)
E
0

found the question interesting - did not have an answer myself.. but located an interesting resource - also discussing calendars.

Calendar converter

Endolymph answered 7/1, 2010 at 12:52 Comment(0)
D
0

The below code will work till the time last 2 days are considered as weekends in cultures.

:)

/// <summary>
/// Returns true if the specified date is weekend in given culture
/// is in. 
/// </summary>
public static bool IsItWeekend(DateTime currentDay, CultureInfo cultureInfo)
{
    bool isItWeekend = false;

    DayOfWeek firstDay = cultureInfo.DateTimeFormat.FirstDayOfWeek;

    DayOfWeek currentDayInProvidedDatetime = currentDay.DayOfWeek;

    DayOfWeek lastDayOfWeek = firstDay + 4;

    if (currentDayInProvidedDatetime == lastDayOfWeek + 1 || currentDayInProvidedDatetime == lastDayOfWeek + 2)
        isItWeekend = true;

    return isItWeekend;         
}

Amit Tonk

Dogfish answered 12/10, 2013 at 13:25 Comment(0)

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