Is there any faster solution than this?
After spending some time in googling and playing with other's code, I made a quick fix and reusable function works well for numbers up to 99,99,99,999.
number2text(1234.56); will return ONE THOUSAND TWO HUNDRED AND THIRTY-FOUR RUPEE AND FIFTY-SIX PAISE ONLY .
function number2text(value) {
var fraction = Math.round(frac(value)*100);
var f_text = "";
if(fraction > 0) {
f_text = "AND "+convert_number(fraction)+" PAISE";
}
return convert_number(value)+" RUPEE "+f_text+" ONLY";
}
function frac(f) {
return f % 1;
}
function convert_number(number)
{
if ((number < 0) || (number > 999999999))
{
return "NUMBER OUT OF RANGE!";
}
var Gn = Math.floor(number / 10000000); /* Crore */
number -= Gn * 10000000;
var kn = Math.floor(number / 100000); /* lakhs */
number -= kn * 100000;
var Hn = Math.floor(number / 1000); /* thousand */
number -= Hn * 1000;
var Dn = Math.floor(number / 100); /* Tens (deca) */
number = number % 100; /* Ones */
var tn= Math.floor(number / 10);
var one=Math.floor(number % 10);
var res = "";
if (Gn>0)
{
res += (convert_number(Gn) + " CRORE");
}
if (kn>0)
{
res += (((res=="") ? "" : " ") +
convert_number(kn) + " LAKH");
}
if (Hn>0)
{
res += (((res=="") ? "" : " ") +
convert_number(Hn) + " THOUSAND");
}
if (Dn)
{
res += (((res=="") ? "" : " ") +
convert_number(Dn) + " HUNDRED");
}
var ones = Array("", "ONE", "TWO", "THREE", "FOUR", "FIVE", "SIX","SEVEN", "EIGHT", "NINE", "TEN", "ELEVEN", "TWELVE", "THIRTEEN","FOURTEEN", "FIFTEEN", "SIXTEEN", "SEVENTEEN", "EIGHTEEN","NINETEEN");
var tens = Array("", "", "TWENTY", "THIRTY", "FOURTY", "FIFTY", "SIXTY","SEVENTY", "EIGHTY", "NINETY");
if (tn>0 || one>0)
{
if (!(res==""))
{
res += " AND ";
}
if (tn < 2)
{
res += ones[tn * 10 + one];
}
else
{
res += tens[tn];
if (one>0)
{
res += ("-" + ones[one]);
}
}
}
if (res=="")
{
res = "zero";
}
return res;
}