Express.JS get url path without any additional parameters

Question

Is there any straightforward way to get URL path segment without any additional data (url parameters, css '#', etc.)

for example:

full URL: http://example.com/panel/list
path segment I want to get: /panel/list

full URL: http://example.com/panel/list?user=joe
path segment I want to get: /panel/list

full URL: http://example.com/panel/list#header
path segment I want to get: /panel/list

And any other combination of data that is not path segment of my URL

Moonlighting

Does this answer your question? node.js with express how to remove the query string from the url – Bilbao

Answer 1

I think you can use req.baseUrl + req.path.

And for full URL use req.originalUrl.

Parrisch

but if I type /admin I get /admin/ instead – Moonlighting

Edit, I just used replace to trim last trailing slash (req.baseUrl + req.path).replace(/\/$/, "") – Moonlighting

Answer 2

For full url without any parameters, you can use req.protocol + '://' + req.get('host') + req.baseUrl + req.path;

Gony

Answer 3

In frontend you can use window.location.pathname.

Louvre