This is the snippet:
String myTime = someTime / 1e9d + ",";
someTime
is derived by using System.nanoTime()
. What does 1e9d
do here?
This is the snippet:
String myTime = someTime / 1e9d + ",";
someTime
is derived by using System.nanoTime()
. What does 1e9d
do here?
1e9
means 10^9
2d
means 2 as double
e.g.
1e9
=> 1.0E910e9
=> 1.0E10See also the Floating-Point Literals section of The Java™ Tutorials.
1e-3
–
Inkster The suffix d denotes a double number. If the number wasn't treated as a floating point number, then the division would be considered an integer division, returning an integer (e.g. 3/2=1).
1e9 is simply 10^9. The conversion seems to be from nanoseconds to seconds.
--EDIT--
Ingo correctly points out that 10e9 is already evaluated by java to a double (see this part of the spec for details). Therefore the 'd' isn't needed in this case.
10e9
is already enough to establis that it is a double, at least in Java. Hence the d
suffix is really superfluous here. –
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