Extract zip contents into directory with same name as zip file, retain directory structure [closed]
Asked Answered
C

2

12

I would like to write a bat script to do the following:

Use 7 Zip to extract files from an existing zip file, into a folder by the same name as the original zip file (bar the .zip extension), and keeping the file & directory structure that was contained in the zip file.

I can extract all the same files into the current directory, by using

"C:\Program Files (x86)\7-Zip\7z.exe" e  myZipFile.zip
Clumsy answered 30/1, 2017 at 9:31 Comment(1)
@Clumsy On using 7-Zip from command line it is always advisable to open help of 7-Zip - the file 7-zip.chm in program files folder of 7-Zip - and read in help on tab Contents the pages listed under list item Command Line Version. The commands e and x are both explained in help as well as all other commands and switches. You would have just needed to read the help.Fingertip
F
7

Reading the help of the 7z-command by just typing "C:\Path To\7-Zip\7z.exe" gets the help with all possible arguments. Here we find the following interesting ones:

 e : Extract files from archive (without using directory names)

and

x : eXtract files with full paths

Trial and error shows that the latter is the one fitting your desired behaviour without bigger effort :)

After the comment by @BadmintonCat here is the addition that will create a folder to zip everything into (use as batch script with the file as argument):

@echo off

SET "filename=%~1"
SET dirName=%filename:~0,-4%

7z x -o"%dirName%" "%filename%"

From the help: -o{Directory} : set Output directory. 7z will create the directory if it does not already exist.

Facetiae answered 30/1, 2017 at 10:6 Comment(0)
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8

Just use the command: 7z x *.zip -o\*

Exclaim answered 8/4, 2020 at 22:45 Comment(3)
I'm not sure that's going to do what he wants. The -o option needs a specific directory named. Using -o\* is either going to expand to all files (and probably error) or it will create a directory actually named * (also not what he wants).Komi
Replace *.zip with actual name of the zip file and it works great. 7z e yourfile.zip -o\*Selfconsistent
find . -name "*.zip" -exec 7z x "{}" -o\* \; based on the answer and commentsEndure
F
7

Reading the help of the 7z-command by just typing "C:\Path To\7-Zip\7z.exe" gets the help with all possible arguments. Here we find the following interesting ones:

 e : Extract files from archive (without using directory names)

and

x : eXtract files with full paths

Trial and error shows that the latter is the one fitting your desired behaviour without bigger effort :)

After the comment by @BadmintonCat here is the addition that will create a folder to zip everything into (use as batch script with the file as argument):

@echo off

SET "filename=%~1"
SET dirName=%filename:~0,-4%

7z x -o"%dirName%" "%filename%"

From the help: -o{Directory} : set Output directory. 7z will create the directory if it does not already exist.

Facetiae answered 30/1, 2017 at 10:6 Comment(0)

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