There is a difference between using child_process.exec() and child_process.execFile() in that the latter won't spawn a shell whereas the former will.
Nodejs documentation states:
On Windows, however, .bat and .cmd files are not executable on their own without a terminal, and therefore cannot be launched using child_process.execFile(). When running on Windows, .bat and .cmd files can be invoked using child_process.spawn() with the shell option set, with child_process.exec(), or by spawning cmd.exe and passing the .bat or .cmd file as an argument (which is what the shell option and child_process.exec() do).
I could launch them... though not without problem.
My observations:
- Running the following
child_process.execFile('ls', ...)
works on Linux whereas child_process.execFile('dir', ...)
doesn't work on Windows.
- specifying the fullpath to the protractor executable on Windows, e.g.
child_process.execFile('C:\\Users\\Jperl\\AppData\\Roaming\\npm\\protractor.cmd', ...)
works as expected! No shell means we don't have access to the path variable.
Don't use execFile for Windows at all. Instead use either spawn
or exec
:
var protractor = child_process.spawn('protractor', ['./src/convertedJs/tempProtractorconfig.js'], {shell: true});
or
var protractor = child_process.spawn('cmd', ['/c', 'protractor', './src/convertedJs/tempProtractorconfig.js']);