You could add some sort of collection to your lexer class. This collection will hold all runtime-words. Then you add some custom code inside the rule that could possibly match these runtime-words and change the type of the token if it is present in the collection.
Demo
Let's say you want to parse the input:
"foo bar baz"
and at runtime, the words "foo"
and "baz"
should become special runtime words. The following grammar shows how to solve this:
grammar RuntimeWords;
tokens {
RUNTIME_WORD;
}
@lexer::members {
private java.util.Set<String> runtimeWords;
public RuntimeWordsLexer(CharStream input, java.util.Set<String> words) {
super(input);
runtimeWords = words;
}
}
parse
: (w=. {System.out.printf("\%-15s :: \%s \n", tokenNames[$w.type], $w.text);})+ EOF
;
Word
: ('a'..'z' | 'A'..'Z')+
{
if(runtimeWords.contains(getText())) {
$type = RUNTIME_WORD;
}
}
;
Space
: ' ' {skip();}
;
And a little test class:
import org.antlr.runtime.*;
import java.util.*;
public class Main {
public static void main(String[] args) throws Exception {
Set<String> words = new HashSet<String>(Arrays.asList("foo", "baz"));
ANTLRStringStream in = new ANTLRStringStream("foo bar baz");
RuntimeWordsLexer lexer = new RuntimeWordsLexer(in, words);
CommonTokenStream tokens = new CommonTokenStream(lexer);
RuntimeWordsParser parser = new RuntimeWordsParser(tokens);
parser.parse();
}
}
which will produce the following output:
RUNTIME_WORD :: foo
Word :: bar
RUNTIME_WORD :: baz
Demo II
Here's another demo that is more tailored to your problem (I skimmed your question too quickly at first, but I'll leave my first demo in place because it might come in handy for someone). There's not much comments in it, but my guess is that you won't have problems grasping what happens (if not, don't hesitate to ask for clarification!).
grammar RuntimeWords;
@lexer::members {
private java.util.Set<String> runtimeWords;
public RuntimeWordsLexer(CharStream input, java.util.Set<String> words) {
super(input);
runtimeWords = words;
}
private boolean runtimeWordAhead() {
for(String word : runtimeWords) {
if(ahead(word)) {
return true;
}
}
return false;
}
private boolean ahead(String word) {
for(int i = 0; i < word.length(); i++) {
if(input.LA(i+1) != word.charAt(i)) {
return false;
}
}
return true;
}
}
parse
: (w=. {System.out.printf("\%-15s :: \%s \n", tokenNames[$w.type], $w.text);})+ EOF
;
Word
: {runtimeWordAhead()}?=> ('a'..'z' | 'A'..'Z')+
| 'abc'
;
Space
: ' ' {skip();}
;
and the class:
import org.antlr.runtime.*;
import java.util.*;
public class Main {
public static void main(String[] args) throws Exception {
Set<String> words = new HashSet<String>(Arrays.asList("BBB", "CDEFG"));
ANTLRStringStream in = new ANTLRStringStream("BBB abc CDEFG");
RuntimeWordsLexer lexer = new RuntimeWordsLexer(in, words);
CommonTokenStream tokens = new CommonTokenStream(lexer);
RuntimeWordsParser parser = new RuntimeWordsParser(tokens);
parser.parse();
}
}
will produce:
Word :: BBB
Word :: abc
Word :: CDEFG
Be careful if some of your runtime words start with another one. For example, if your runtime words contain "stack"
and "stacker"
, you want the longer word to be checked first! Sorting the set based on the length of the strings should be in order.
One final word of caution: if only "stack"
is in your runtime word list and the lexer encounters "stacker"
, then you probably don't want to create a "stack"
-token and leave "er"
dangling. In that case, you'll want to check if the character after the last char in the word
is not a letter:
private boolean ahead(String word) {
for(int i = 0; i < word.length(); i++) {
if(input.LA(i+1) != word.charAt(i)) {
return false;
}
}
// charAfterWord = input.LA(word.length())
// assert charAfterWord != letter
// note that charAfterWord could also be EOF
return ... ;
}