How to have two functions that call each other C++

Question

I have 2 functions like this that does obfuscation on if loop:

void funcA(string str)
{
    size_t f = str.find("if");
    if(f!=string::npos)
    {
        funcB(str);        //obfuscate if-loop
    }
}

void funcB(string str)
{
     //obfuscate if loop
     funcA(body_of_if_loop);     //to check if there is a nested if-loop
}

The problem with this would be that funcA would not be able to see funcB and vice versa if I put funcB before funcA.

Would appreciate any help or advice here.

Worthen

Why does everybody call it an if loop? There's absolutely no looping involved. – Konyn

@Konyn well, it replaces for-loop construct, does it not? – Dandify

Answer 1

What you want is forward declaration. In your case:

void funcB(string str);

void funcA(string str)
{
    size_t f = str.find("if");
    if(f!=string::npos)
    {
        funcB(str);        //obfuscate if-loop
    }
}

void funcB(string str)
{
     //obfuscate if loop
     funcA(body_of_if_loop);     //to check if there is a nested if-loop
}

Hashimoto

Answer 2

A forward declaration would work:

void funcB(string str); 

void funcA(string str)
{
    size_t f = str.find("if");
    if(f!=string::npos)
    {
        funcB(str);        //obfuscate if-loop
    }
}

void funcB(string str)
{
     //obfuscate if loop
     funcA(body_of_if_loop);     //to check if there is a nested if-loop
}

Dotson