Why can not we get outerHTML of an svg element with element.outerHTML
property?
Is this way is the best http://jsfiddle.net/33g8g/ for getting svg source code?
Why can not we get outerHTML of an svg element with element.outerHTML
property?
Is this way is the best http://jsfiddle.net/33g8g/ for getting svg source code?
It's not accessible via outerHTML because SVG is not HTML -- it's a separate XML specification.
That's why, for example, your svg node in that example has its own namespace defined (xmlns="http://www.w3.org/2000/svg
).
Your example may be the most expedient for a one-off query, but it's actually possible to dig in using native attributes. It just takes a bit more work.
Let's use the linked sample node:
<svg xmlns="http://www.w3.org/2000/svg" version="1.1">
<text x="0" y="15" fill="black">An SVG element.</text>
</svg>
If you want to extract the namespace and version, use the attributes
property.
var svgElement = $('svg')[0]; // using your example
console.log(svgElement.attributes.xmlns); // outputs "http://www.w3.org/2000/svg"
console.log(svgElement.attributes.version); // outputs "1.1"
If you want to extract the actual contents, iterate over the children. Similar to the above, a non-text node's attributes
collection will contain the x/y values (etc).
Without using jQuery, using your example again:
for (var i = 0; i < svgElement.childNodes.length; i++) {
var child = svgElement.childNodes[i];
if (child.nodeType == 1) {
console.log(child.attributes[0].name); // "x"
console.log(child.attributes[0].value); // "0"
console.log(child.attributes[1].name); // "y"
console.log(child.attributes[1].value); // "15"
}
}
Here's an updated Fiddle, a bit more elegantly demonstrating the possibilities: http://jsfiddle.net/33g8g/8/
SVGElements don't have outerHTML property.
You can define like this in pure Javascript
Object.defineProperty(SVGElement.prototype, 'outerHTML', {
get: function () {
var $node, $temp;
$temp = document.createElement('div');
$node = this.cloneNode(true);
$temp.appendChild($node);
return $temp.innerHTML;
},
enumerable: false,
configurable: true
});
Or a one line jQuery solution would be
$('<div>').append($(svgElement).clone()).html();
Reference: https://gist.github.com/jarek-foksa/2648095
if (!('outerHTML' in SVGElement.prototype)) { /** */ }
around the polyfill –
Palinode This is an easier solution and it works great in FF, Chrome, IE. Honor goes to Philipp Wrann.
outerHtml is not working in IE
new XMLSerializer().serializeToString(document.querySelector('#b'))
SVGElement
Example: const element: SVGElement = canvas.getPreview();
const svgString: string = w XMLSerializer().serializeToString(element);
–
Instrumentalism 2013 update: The innerHTML
and outerHTML
are going to be supported for svg elements too, per the DOM Parsing specification.
A patch for this has been landed in Blink/Chrome and will become available soon, see http://code.google.com/p/chromium/issues/detail?id=311080.
It's not accessible via outerHTML because SVG is not HTML -- it's a separate XML specification.
That's why, for example, your svg node in that example has its own namespace defined (xmlns="http://www.w3.org/2000/svg
).
Your example may be the most expedient for a one-off query, but it's actually possible to dig in using native attributes. It just takes a bit more work.
Let's use the linked sample node:
<svg xmlns="http://www.w3.org/2000/svg" version="1.1">
<text x="0" y="15" fill="black">An SVG element.</text>
</svg>
If you want to extract the namespace and version, use the attributes
property.
var svgElement = $('svg')[0]; // using your example
console.log(svgElement.attributes.xmlns); // outputs "http://www.w3.org/2000/svg"
console.log(svgElement.attributes.version); // outputs "1.1"
If you want to extract the actual contents, iterate over the children. Similar to the above, a non-text node's attributes
collection will contain the x/y values (etc).
Without using jQuery, using your example again:
for (var i = 0; i < svgElement.childNodes.length; i++) {
var child = svgElement.childNodes[i];
if (child.nodeType == 1) {
console.log(child.attributes[0].name); // "x"
console.log(child.attributes[0].value); // "0"
console.log(child.attributes[1].name); // "y"
console.log(child.attributes[1].value); // "15"
}
}
Here's an updated Fiddle, a bit more elegantly demonstrating the possibilities: http://jsfiddle.net/33g8g/8/
Using jQuery, you can easily create a temporary HTML wrapper around any element that doesn't support outerHTML :
function wrappedHtml(elt){
var wrapped = elt.wrap("<wrap></wrap>").parent().html();
elt.unwrap();
return wrapped;
}
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