Lua socket asynchronous calls
Asked Answered
W

3

13

I am writing a program that uses Lua socket to communicate with a http server. The API that I am using is "socket.http.request", and I have found that it is synchronous. My understanding is that it waits until it gets some response or time outs. Is my understanding correct? If so, I'd prefer to use an asynchronous API.

I also found another API "socket.http.request_cb", which calls a call back function when the request is processed. However, it doesn't seem to work here. (This API is not available on the version that I'm using.) I'm using Lua 5.1 and Lua socket 2.0.2 here. Could anyone let me know which version of Lua or Lua socket has this API?

Weisler answered 26/4, 2011 at 19:27 Comment(1)
possible duplicate of Problem with luasocketCyanic
B
12

With connection:settimeout() you can set a time out for a connection. This is used in this example of a parallel downloader for Lua Socket:

function download (host, file, port)
    port = port or 80
    print (host, file, port)    
    local connectStatus, myConnection = pcall (socket.connect,host,port)
    if (connectStatus) then
        myConnection:settimeout(0.01) -- do not block you can play with this value
        local count = 0 -- counts number of bytes read
        -- May be easier to do this LuaSocket's HTTP functions
        myConnection:send("GET " .. file .. " HTTP/1.0\r\n\r\n")
        local lastStatus = nil
        while true do
            local buffer, status, overflow = receive(myConnection, lastStatus)
            -- If buffer is not null the call was a success (changed in LuaSocket 2.0)
            if (buffer ~= nil) then
                 io.write("+")
                 io.flush()
                 count = count + string.len(buffer)
            else
                print ("\n\"" .. status .. "\" with " .. string.len(overflow) .. " bytes of " .. file)
                io.flush()
                count = count + string.len(overflow)
            end
            if status == "closed" then break end
                lastStatus=status
            end
        myConnection:close()
        print(file, count)
    else
        print("Connection failed with error : " .. myConnection)
        io.flush()
    end
end

threads = {} -- list of all live threads

function get (host, file, port)
    -- create coroutine
    local co = coroutine.create(
        function ()
            download(host, file, port)
        end)
    -- insert it in the 
    table.insert(threads, co)
end

function receive (myConnection, status)
    if status == "timeout" then
        print (myConnection, "Yielding to dispatcher")
        io.flush()
        coroutine.yield(myConnection)
    end
    return myConnection:receive(1024)
end

function dispatcher ()
    while true do
        local n = table.getn(threads)
        if n == 0 then break end -- no more threads to run
        local connections = {}
        for i=1,n do
            print (threads[i], "Resuming")
            io.flush()
            local status, res = coroutine.resume(threads[i])
            if not res then -- thread finished its task?
                table.remove(threads, i)
                break
            else -- timeout
                table.insert(connections, res)
            end
        end
        if table.getn(connections) == n then
            socket.select(connections)
        end
    end
end

host = "www.w3.org"
get(host, "/TR/html401/html40.txt")
get(host,"/TR/2002/REC-xhtml1-20020801/xhtml1.pdf")
get(host,"/TR/REC-html32.html")
get(host,"/TR/2000/REC-DOM-Level-2-Core-20001113/DOM2-Core.txt")
dispatcher()
Buckman answered 27/4, 2011 at 19:38 Comment(0)
D
1

I am doing all IO multiplexing stuff with lua-ev. It an event loop implementation similar to the one behind node.js. One thread, no races.

Dixson answered 5/11, 2013 at 22:42 Comment(0)
B
0

You may find some inspiration in luaThread. One of its demos is an asynchronous wget.

A recently developed threading library lua-llthreads supports the ZMQ "socket library that acts as a concurrency framework" with lua-zmq

Brownstone answered 28/4, 2011 at 15:0 Comment(0)

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