Actually I am thinking about trivially destructible objects, not only about POD (I am not sure POD can have base class).
When I read this explanation for is_trivially_destructible from cppreference I notice this:
Storage occupied by trivially destructible objects may be reused without calling the destructor.
So, it is safe to do that:
struct A {
int a;
};
struct B : A {
int b;
};
int main() {
A* a = new B;
delete a;
}
B::~B()
won't be called - and AFAIK (please correct if I am wrong) the entire memory will be freed. And B::~B()
for sure is trivial.
I know this code smells badly, but my question is only about safeness of this code...
a
will always point to aB
instance and thatB
is going to remain trivially destructible? If someone modifiesB
or replaces it with a non-trivially destructible subclass ofB
he will silently introduce a bug. – Tarbox