I'm just starting with Ruby and I personally find the following to be a violation of the "principle of least surprise". And that is, quoting from the documentation, that uniq! "removes duplicate elements from self. Returns nil if no changes are made (that is, no duplicates are found)."
Can anybody explain this, which seems completely counter-intuitive to me? This means that rather than being able to write one line of code below by appending .uniq! to end the first line, I instead have to write the following two lines:
hooks = IO.read(wt_hooks_impl_file).scan(/wt_rt_00\w{2}/)
hooks = hooks.uniq
Or am I missing something, a better way?
EDIT:
I understand that uniq! modifies its operand. Here's the problem illustrated better I hope:
hooks = IO.read(wt_hooks_impl_file).scan(/wt_rt_00\w{2}/)
puts hooks.length #50
puts hooks.uniq!.length #undefined method `length' for nil:NilClass
I contend that the way uniq! works makes it completely senseless and useless. Sure in my case as pointed out I could just append .uniq to the first line. However later in the same program I am pushing elements onto another array inside of a loop. Then, under the loop, I'd like to "de-dupe" the array, but I dare not write 'hooks_tested.uniq!' because it could return nil; instead I must write hooks_tested = hooks_tested.uniq
Indeed I contend this is a particularly egregious mis-feature in that it is a well known principle that, when devising a method that returns an array, one should always at least return an empty array, rather than nil
uniq!
. That would probably be what Matz had in mind. ;-) – Manizalesuniq
returns the original one. Whenuniq
finds no duplicates, it returns the array itself. seriously wtf. – Ellieuniq?
notuniq!
– Ellie