QImage img( "Red.jpg" );
if ( false == img.isNull() )
{
QVector<QRgb> v = img.colorTable(); // returns a list of colors contained in the image's color table.
for ( QVector<QRgb>::const_iterator it = v.begin(), itE = v.end(); it != itE; ++it )
{
QColor clrCurrent( *it );
std::cout << "Red: " << clrCurrent.red()
<< " Green: " << clrCurrent.green()
<< " Blue: " << clrCurrent.blue()
<< " Alpha: " << clrCurrent.alpha()
<< std::endl;
}
}
However this example above does returns the color table. Color table does not includes same colors twice. They will be added once in order of appearance.
If you want to get each pixels color, you can use next lines:
for ( int row = 1; row < img.height() + 1; ++row )
for ( int col = 1; col < img.width() + 1; ++col )
{
QColor clrCurrent( img.pixel( row, col ) );
std::cout << "Pixel at [" << row << "," << col << "] contains color ("
<< clrCurrent.red() << ", "
<< clrCurrent.green() << ", "
<< clrCurrent.blue() << ", "
<< clrCurrent.alpha() << ")."
<< std::endl;
}
bits()
depends heavily on the image format. Try to convert the format to something more suitable for your scenario, e.g.img = img.convert(QImage::Format_ARGB32)
. Then the bytes should come out as0, 255, 0, 0, [loop]
if I'm not mistaken. – Gunthar