Well I worked on this for a project I guess it's ok to show the code here, my scenario may not be exactly like urs but similar, so my case was I stored the state of an environment, i wanted to store the changes to this environment but i decided not to use store the whole array for every change that would not be smart i guess so i used something called JSON-Patch
its a cool protocol to monitor the changes in a json array and i can store those patches because they are smaller than my massive array.
const jiff = require('jiff')
/**
* @description function chacks the difference between two states and returns the differece to be stored
* @param oldState @type Array
* @param newState @type Array
*/
///note when changing from a to b your looking for what would make b a not a b
const createAnOpp = (newState, oldState) => {
// console.log("\n newState",newState)
// console.log("\n oldState",oldState)
// console.log("\n new opp", jiff.diff( JSON.parse(JSON.stringify(newState)),JSON.parse(JSON.stringify(oldState))))
return jiff.diff( JSON.parse(JSON.stringify(newState)),JSON.parse(JSON.stringify(oldState)) )
};
/**
* @description takes an operation and applies the patch operation to data passed on by reference
* @param opperation @type reference
* @param data @type reference
*/
const perfomOpp =(opperation,data )=>{
return jiff.patch(opperation, data);
}
/**
* @description applies the do redo or undo feature based on the command sent to it
* @param code @type number 1 = redo 0 = undo
* @param data @type Array
* @param opperation
* @returns an object which is the state and the redo opp { newOpp,latestState}
*/
const performCall = (code,data,operation)=>{
switch(code){
case(0): ////undo
{
//patches on the list are stored to undo(go back to previous state)
const latestState = perfomOpp(operation,data)
// console.log("\n latestState",latestState)
// console.log("\n oldState",data)
return {
latestState ,
newOpp:createAnOpp(latestState,data)
}
break
}
case(1): ////redo
{
//patches on the list are stored to undo(go back to previous state)
const latestState = perfomOpp(operation,data)
// console.log('\n neww opp stage 1==>',createAnOpp(data,latestState))
return {
latestState ,
newOpp:createAnOpp(latestState,data)
}
break
}
}
}
///init state
var a = [
{ name: 'a' },
{ name: 'b' },
{ name: 'c' },
]
console.log("\n current Array ", a)
var opps = []
var pointerToOps = 0
var b = a.slice();
b.push({ name: 'd' });
// console.log("\n b==>",b)
console.log("\n current Array ", b)
// Generate diff (ie JSON Patch) from a to b
var patch = createAnOpp(b, a);
opps.push(patch)//store the diff when its been changed
pointerToOps = opps.length - 1
// console.log("\n opps1==>",JSON.stringify(opps))
//update the pointer
var c = b.slice();
c.push({ name: 'e' });
console.log("\n current Array ", c)
// console.log("\n c==>",c)
// Generate diff (ie JSON Patch) from a to b
var patch = createAnOpp(c, b);
opps.push(patch)//store the diff when its been changed
pointerToOps = opps.length - 1
console.log("\n opp ", opps)
//update the pointer
//now ive applied change and what not time to undo
const newData = performCall(0,c,opps[pointerToOps])
// //now i have to go take a step back with the pointer
opps[pointerToOps] = newData.newOpp//replacing undo opp with redo opp
pointerToOps = --pointerToOps
// console.log("\n opps3==>",JSON.stringify(opps))
console.log("\n current Array ", newData.latestState)
const newData2 = performCall(0,newData.latestState,opps[pointerToOps])
//now i have to go take a step back with the pointer
console.log("\n current Array ", newData2.latestState)
opps[pointerToOps] = newData2.newOpp//replacing undo opp with redo opp
pointerToOps = --pointerToOps
pointerToOps = ++pointerToOps
const newData3 = performCall(1,newData2.latestState,opps[pointerToOps])
//now i have to go take a step back with the pointer
opps[pointerToOps] = newData3.newOpp//replacing undo opp with redo opp
console.log("\n current Array ", newData3.latestState)
pointerToOps = ++pointerToOps
const newData4 = performCall(1,newData3.latestState,opps[pointerToOps])
//now i have to go take a step back with the pointer
opps[pointerToOps] = newData4.newOpp//replacing undo opp with redo opp
console.log("\n current Array ", newData4.latestState)
console.log("\n opp ", opps)