What does it mean for a Java program to be JIT'ed and does it make the execution a lot more faster? Or are there bytecodes which are not JIT'ed?
Is there a way to turn off JIT compiler and is there a performance impact by doing so?
Asked Answered
There is two ways to disable the JIT
-Djava.compiler=NONE
or this will almost never compile anything
-XX:CompileThreshold=2000000000
or on IBM JVM
-nojit
Disabling the JIT can slow down your code a lot e.g. 50x but not always. If you spend most of your time doing IO or GUI updates you might find it makes little difference.
I am learning java and have so many doubts regarding most of the stuff.....thank you for your answer. :) further I would like to know what compiler comes in to play when we disable JIT? –
Forebrain
@Forebrain disabling the JIT means there is no compiler. Instead the code is only run in interpreter mode. –
Galibi
I was a bit surprised that this ancient
java.compiler
property still works despite you can’t really use it to specify an actual compiler implementation, so I investigated a bit and found JDK-8227229 which explains a bit of the history and also reveals the surprising fact that specifying -Xdebug
makes -Djava.compiler=NONE
ineffective, so using -Xint
has always been the more reliable option. –
Kiely For IBM the correct option is -Xnojit or -Xint
This does not provide an answer to the question. To critique or request clarification from an author, leave a comment below their post. - From Review –
Acute
When I wrote his answer I was not allowed to comment. Otherwise, I would have. –
Doherty
In HotSpot VM JIT compilation can be disabled with the option -XX:-UseCompiler
which skips compiler threads initialization.
It is true
by default:
product(bool, UseCompiler, true,
"Use Just-In-Time compilation")
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