In BASH, How do i replace \r from a variable that exist in a file written using HTML <textarea></textarea>

Question

How do i replace the \r?

#!/bin/bash
...

# setup
if [[ $i =~ $screen ]]; then

    ORIGINAL=${BASH_REMATCH[1]}          # original value is: 3DROTATE\r
    AFTER   =${ORIGINAL/\\r/}            # does not replace \r
    myThirdPartyApplication -o $replvar  # FAILS because of \r

fi

Preponderance

can't have spaces around the = – Eisk

Answer 1

You could use sed, i.e.,

AFTER=`echo $ORIGINAL | sed 's/\\r//g'`

Electroluminescence

It drops $' in the beginning also. Cool. – Phenomenon

Worked!!! Just a little improve: spaces are not allowed in value assignation : AFTER=echo... – Harbor

Answer 2

This should remove the first \r.

AFTER="${ORIGINAL/$'\r'/}"

If you need to remove all of them use ${ORIGINAL//$'\r'/}

Lunation

IMHO this is the best answer, as it avoids the overhead of launching an external program (such as sed or tr). The $ at the beginning of $'\r' is essential to have the \r converted to a 'carriage return' character in the pattern of things to be replaced. Maybe it's not obvious, the \r is replaced with nothing (the absence of characters between the last / and }. – Windhover

this maybe a top voted answer and works for me too. but there is a problem reported by shellcheck: github.com/koalaman/shellcheck/wiki/SC3060 – Chivaree

Answer 3

Another option is to use 'tr' to delete the character, or replace it with \n or anything else.

 ORIGINAL=$(echo ${BASH_REMATCH[1]} | tr -d '\r')

Tamatave

Answer 4

Just use a literal ^M character, it has no meaning to bash.

Vav

Answer 5

Similar to @tharrrk's approach, this parameter substitution also remove the last '\r':

AFTER="${ORIGINAL%'\r'}"

Isfahan